Describe three skills people use to conduct scientific investigations

Convert each quantity to the indicated units. a. 3.01g to cg. b. 6200m to km

miss Akunina [59]

a. 301 cg

b. 6.2 km

Explanation:

a. knowing that 1 gram (g) is equal to 100 centigrams (cg) we devise the following reasoning:

if 1 g is equal to 100 cg

then 3.01 g are equal to X cg

X = (3.01 × 100) / 1 = 301 cg

b. knowing that 1 kilometer (km) is equal to 1000 meters (m) we devise the following reasoning:

if 1 km is equal to 1000 m

then Y km are equal to 6200 m

Y = (6200 × 1) / 1000 = 6.2 km

Learn more about:

converting units of measurement

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5 0

3 years ago

What is the empirical formula for a compound if 300.00 g of it is known to contain 82.46224 g of molybdenum, 45.741 g of chlorin

Marysya12 [62]

Answer:

MoClBr₂

Explanation:

First we calculate the mass of bromine in the compound:

300.00 g - (82.46224 g + 45.741 g) = 171.79676 g

Then we calculate the number of moles of each element, using their respective molar masses:

82.46224 g Mo ÷ 95.95 g/mol = 0.9594 mol Mo

45.741 g Cl ÷ 35.45 g/mol = 1.290 mol Cl

171.79676 g Br ÷79.9 g/mol = 2.150 mol Br

Now we divide those numbers of moles by the lowest number among them:

0.9594 mol Mo / 0.9594 = 1

1.290 mol Cl / 0.9594 = 1.34 ≅ 1

2.150 mol Br / 0.9594 = 2.24 ≅ 2

Meaning the empirical formula is MoClBr₂.

8 0

3 years ago

The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles

sergejj [24]

Answer: The expression for equilibrium constant is $K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For the general chemical equation:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_c$ is given as:

$K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

For the given chemical reaction:

$2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)$

The expression for $K_{eq}$ is given as:

$K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}$

The concentration of solid is taken to be 0.

So, the expression for $K_{eq}$ is given as:

$K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}$

3 0

3 years ago

Calculate the mass, in grams, of each sample. a. 1.1 * 1023 gold atoms b. 2.82 * 1022 helium atoms c. 1.8 * 1023 lead atoms d. 7

Vlada [557]

Answer:blablablablablabla

Explanation:

Blablabla

5 0

3 years ago

Which of the following results from acid deposition? View Available Hint(s) Which of the following results from acid deposition?

ASHA 777 [7]

Answer:

Objects made of stone, like marble headstones, are worn away.

Explanation:

Acid deposition on earth is mostly as a result of acid rain. Acid rain forms which oxides of non-metals such as nitrogen and carbon dissolves in rain water to produce weak acid.

This weak acid that is produced easily wears away materials made up of marble and other sculptures. The most active of the acid is weak carbonic acid produced by dissolution of carbon dioxide in rain water.

6 0

2 years ago