In 2010 an item cost $9.00. The price increase by 1.5% each
1 answer:
Answer:
Step-by-step explanation:
Let P be price after t year . From the formula of compounding
P = 9 
Taking log to the base e on both sides
ln P = ln 9 + t ln 1.015
= (2.197 + .0149t )
P = 
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B.) a=-5.7
1.6(a)=-9.12
(a)=(-9.12)/(1.6)
a=-5.7
You're answer is (B).-3.
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-5+2=-3
=|-3|
=|-3|
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Answer:
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Step-by-step explanation:
