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sergij07 [2.7K]
3 years ago
10

In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 36 μA current, due to the flow

of electrons. Part A What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?
Physics
1 answer:
laiz [17]3 years ago
6 0

Answer:

n = 2.25 x 10¹⁴ electrons/s

Explanation:

The amount of electric current is defined as the electric charge passing through an area per unit time. Hence:

I = q/t

where,

I = Current

q = amount of charge

t = time interval

but,

q = ne

therefore,

I = ne/t

where,

n = no. of electrons

e = charge on single electron = 1.6 x 10⁻¹⁹ C

t = 1 s (for electrons passing per second)

I = Current = 36 μA = 3.6 x 10⁻⁵ A

Therefore,

3.6 x 10⁻⁵ A = n(1.6 x 10⁻¹⁹ C)/1 s

n = (3.6 x 10⁻⁵ A)/(1.6 x 10⁻¹⁹ C)

<u>n = 2.25 x 10¹⁴ electrons/s</u>

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nata0808 [166]

Answer:

2.85 m

Explanation:

From trigonometry,

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Assuming, The wall, the ladder and the ladder forms a right angle triangle as shown in fig 1, in the diagram attached below.

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Given: ∅ = 68 °, H = 7.6 m.

Substitute into equation 2

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