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Maru [420]
3 years ago
9

Question:

Physics
2 answers:
Hatshy [7]3 years ago
6 0
True
Acceleration is a change in velocity and velocity, in turn is a measure of the speed and direction of motion.

When objects fall to the ground, the gravity causes them to accelerate
valkas [14]3 years ago
5 0

Answer:

the answer is true.

Explanation:

hope it will help you

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Long sand ridges oriented at right angles to the wind are called _____ dunes
S_A_V [24]

The answer is:

Transverse dune

The explanation:

Transverse dune : is abundant barchan dunes It  may merge into barchanoid ridges, which then grade into linear .

The transverse dunes is called that because they lie transverse, or across, the wind direction, with the wind blowing perpendicular to the ridge crest.

It is large, very asymmetrical, elongated dune lying at right angles 90° to the prevailing wind direction.

Transverse dunes have a gently sloping windward side and a steeply sloping leeward side.

They general form in areas of sparse vegetation and abundant sand are transverse dunes.

3 0
3 years ago
Read 2 more answers
Two circular loops of wire, each containing a single turn, have the same radius of 5.10 cm and a common center. The planes of th
Fofino [41]

Explanation:

Below is an attachment containing the solution.

8 0
3 years ago
A 4.0 kg object will have a weight of approximately 14.8 N on Mars. What is the gravitational field strength on Mars?
zhannawk [14.2K]
Field strength =force/unit mass
= 14.8N/ 4kg = 3.7N/kg
8 0
3 years ago
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How much heat is released when 6.00 grams of ammonia and 5.00 grams of oxygen?
snow_tiger [21]
11 grams were released.think it help
7 0
3 years ago
Canola oil is less dense than water, so it floats on water, but its index of refraction is 1.47, higher than that of water. When
kupik [55]

Answer:

therefore critical angle c= 69.79°

Explanation:

Canola oil is less dense than water, so it floats over water.

Given n_{canola}= 1.47

which is higher than that of water

refractive index of water n_{water}=1.33

to calculate critical angle of light going from the oil into water

we know that

sinc= \frac{n_{water}}{n_{canola}}

now putting values we get

sinc= \frac{1.33}{1.47}

c= sin^{-1}(\frac{1.33}{1.47} )

c=69.79°

therefore critical angle c= 69.79°

8 0
3 years ago
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