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Lina20 [59]
3 years ago
9

Two spherical balloons are filled with water. The first balloon has a radius of 3 cm, and the second has a radius of 6 cm. How m

uch greater is the volume of water in the larger balloon than in the smaller balloon? Use 3. 14 to approximate pi. Round to the nearest hundredth if necessary. Enter your answer as a decimal in the box.
Physics
2 answers:
Katena32 [7]3 years ago
8 0

Answer:

V = 4/3 R^3

V2 / V1 = (R2 / R1)^3 = 2^3 = 8

8.00

Marianna [84]3 years ago
4 0

The volume of water in the larger balloon is 8 times greater than in the smaller balloon

We'll begin by calculating the volume of each balloon.

<h3>For smaller balloon:</h3>
  • Radius (r) = 3 cm
  • Pi (π) = 3.14
  • Volume (V) =?

V = 4/3 πr³

V = 4/3 × 3.14 × 3³

<h3>V = 113.04 cm³</h3>

<h3>For larger balloon:</h3>
  • Radius (r) = 6 cm
  • Pi (π) = 3.14
  • Volume (V) =?

V = 4/3 πr³

V = 4/3 × 3.14 × 6³

<h3>V = 904.32 cm³</h3>

Finally, we shall determine how much greater the larger balloon is to the smaller balloon

  • Volume of smaller balloon = 113.04 cm³
  • Volume of larger balloon = 904.32 cm³
  • Greatness =?

Greatness => large / small

Large / small = 904.32 / 113.04

Large / small = 8

Cross multiply

<h3>Large = 8 × small </h3>

Therefore, the larger balloon is 8 times greater than the smaller balloon.

Learn more on volume of sphere: brainly.com/question/9178703

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