A cube of copper 2.00cm on a side is suspended by a string. The cube is heated with a burner from 20.0°C to 90.0°C. The air surr
ounding the cube is at atmospheric pressure (1.01×10^5Pa).
a. The increase in volume of the cube.
b. The mechanical work done by the cube to expand against the pressure of the surrounding air.
c. The amount of heat added to the cube.
d. The change in internal energy of the cube.
a. The increase in volume of the cube.
b. The mechanical work done by the cube to expand against the pressure of the surrounding air.
c. The amount of heat added to the cube.
d. The change in internal energy of the cube.
1 answer:
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Angular velocity of the rotating tires can be calculated using the formula,
v=ω×r
Here, v is the velocity of the tires = 32 m/s
r is the radius of the tires= 0.42 m
ω is the angular velocity
Substituting the values we get,
32=ω×0.42
ω= 32/0.42 = 76.19 rad/s
= 76.19× revolution per min
=728 rpm
Angular velocity of the rotating tires is 76.19 rad/s or 728 rpm.
Answer:
Explanation:
Static friction occurs when an object initially starts at rest. When the surfaces of the materials touch, the microscopic unevenness interlock greatest with each other, causing the most friction out of the three.
During sliding friction, an object is already moving or in motion. The microscopic surfaces still interlock, but because the object is in motion, it has a momentum. Therefore, the magnitude of sliding friction is less than that of static friction.
Rolling friction occurs when an object rolls across some surface. Rather than surfaces interlocking, rolling friction is caused by the constant distortion of surfaces. As it rolls, the surfaces of the object are constantly wrapping and changing. This distortion causes the rolling friction. However, it is much less in magnitude when compared to static or sliding friction.