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3 years ago

Can someone please help me with these problems? Any number is ok.

Mathematics

1 answer:

Alex Ar [27]3 years ago

5 0

26) x+x+1+2x+x+3 simplified it is 5x+4 because you need to add all the like terms. when you plug in 3 for x the equation turns into 5(3) +4 so your final answer is 19.

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Does each equation represent exponential decay or exponential growth?

agasfer [191]

An exponential equation is represented as: $\mathbf{y = ab^x}$ , where b represents rate

Exponential growth: $\mathbf{y = 5(7)^x}$ , $\mathbf{y = 3(4.2)^x}$ and $\mathbf{y = 0.6(1.3)^x}$
Exponential decay: $\mathbf{k = 4.2(0.28)^x}$
Neither: $\mathbf{h(x) - 3x + 1.3}$

An exponential equation is said to represent growth, if the rate is greater than 1, while it represents decay if the rate is less than 1.

This means that:

$\mathbf{y = 5(7)^x}$ , $\mathbf{y = 3(4.2)^x}$ and $\mathbf{y = 0.6(1.3)^x}$ represent exponential growth because 5, 4.2 and 1.3 are greater than 1

Also,

$\mathbf{k = 4.2(0.28)^x}$ represents exponential decay because 0.28 is less than 1

While

$\mathbf{h(x) - 3x + 1.3}$ is not an exponential function

Read more about exponential functions at:

brainly.com/question/11487261

5 0

2 years ago

Below is the graph of f(x)=2In(x). how would you describe the graph of g(x)=4In(x)

Andreyy89

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now... with that template in mind, let's see yours

$\bf \begin{array}{llll}
g(x)=&4ln(x)\implies &2(2)ln(x)\\
&\uparrow &\uparrow \\
&A&A
\end{array}$

A is twice as large as in f(x), thus the graph shrinks twice as much in g(x)

7 0

4 years ago

Read 2 more answers

t a gas station, 15 gallons of gas has a price of $17.55 and 18 gallons of gas has a price of $21.06. Write a direct variation e

yaroslaw [1]

Use constant of variation y =kx i.e
15 gallons k=>17.55
k gallons =17.55/15=1.17

18 gallons k=>21.06
k gallons =21.06/18=1.17

Therefore ans => y=1.17x

7 0

3 years ago

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Complete the following statements.

SashulF [63]

The 99.87th percentile, or the area to the left of the 3 standard deviation mark it 99.87% better than everyone/everything else.

6 0

4 years ago

X + 5 = 10 A) x = 2 B) x = 3 C) x = 4 D) x = 5

MrRa [10]

D.) x = 5, because when you plug five in for x, 5 + 5 = 10 is correct.

8 0

3 years ago

Read 2 more answers