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pickupchik [31]
3 years ago
7

Heat measures the average kinetic energy a substance's molecules. TRUE FALSE

Chemistry
1 answer:
hammer [34]3 years ago
7 0

Answer:

False this is like the definition of temperature

Explanation:

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PLEASE HELP!!!! THIS IS DUE AT 12!!!!!​
Nina [5.8K]

Answer:

.

Explanation:

3 0
3 years ago
Leopards and cheetahs look very similar, since both have spotted coats, but the two species of big cats are actually quite diffe
Lisa [10]
The answer is letter A i think
3 0
3 years ago
Type the correct answer in the box. express your answer to three significant figures. an air mattress is filled with 0.55 moles
dmitriy555 [2]

385 L is the volume of the air mattress with 0.55 moles of air inside the mattress and a temperature of 295 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.5 kPa

V=?

n= 0.55 moles of air

T= 295K

R= 8.314 (L kPa/mol K)

Putting value in the given equation:

V= \frac{nRT}{P}  

V = \frac{(0.55 moles)(8.314 L kPa/mol k)(295 K)}{3.5 kPa}

V = 385.4132857 L

And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 litres.

Hence, 385.4132857 L is the volume of the air mattress.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

5 0
2 years ago
Which compound contains both sigma and pi bonds
Misha Larkins [42]
Any compound with multiple covalent bonds
6 0
3 years ago
Read 2 more answers
A quantity of 0.0250 mol of a gas initially at 0.050 L and 19.0°C undergoes a constant-temperature expansion against a constant
KiRa [710]

Answer:

V_2=2.995L\\\\W=248.5J

Explanation:

Hello,

In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

P_1V_1=P_2V_2

So we solve for V_2 by firstly computing the initial pressure:

P_1=\frac{nRT}{V_1}=\frac{0.025mol*0.082\frac{atm*L}{mol*K}*(19+273.15)K}{0.050L}  =11.98atm

V_2=\frac{P_1V_1}{P_2}=\frac{11.98atm*0.050L}{0.200atm}\\ \\V_2=2.995L

Finally, we can compute the work by using the following formula:

W=nRTln(\frac{V_2}{V_1} )=0.025mol*8.314\frac{J}{mol*K}*(19.0+273.15)K*ln(\frac{2.995L}{0.050L}) \\\\W=248.5J

Best regards.

4 0
3 years ago
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