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alexandr1967 [171]
3 years ago
15

The number 0.0007270 is larger than the number 5.7 × 10–3.

Chemistry
1 answer:
klasskru [66]3 years ago
4 0

Answer:

Yes

Explanation:

=5.7×10-3

=5.7×7=39.9

=0.0007270 greater than 5.7× 10-3

OR

=5.7×10

=57-3

=54

So it is greater number

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10) an object has mass of 50g 500mg and 0.1g. express the total mass of the object in grams
Pavel [41]
500 mg in g :

1 g ----------- 1000 mg
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500 x 1 / 1000 => 0.5 g

total mass:

50 g + 0.5 g + 0.1 g => 50.6 g

hope this helps!
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3 years ago
Describe how a chemical change follows the law of conservation of matter.<br> give examples pls
Paha777 [63]

Explanation:

In any chemical change, one or more initial substances change into a different substance or substances. ... According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and kind of atoms after the chemical change as were present before the chemical change

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The carbon atom in coal becomes carbon dioxide when it is burned. The carbon atom changes from a solid structure to a gas but its mass does not change.

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2 years ago
Place the following in order of increasing molar entropy at 298 K.
Genrish500 [490]

Answer:

SO < CO2 < C3H8

Explanation:

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3 0
2 years ago
How can wind produce erosion?
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8 0
2 years ago
3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh
TiliK225 [7]

Answer:

n_{C_6H_{10}}=0.03molC_6H_{10}

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}

Even thought, the volume could be also computed by using its density:

V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}

Best regards.

4 0
2 years ago
Read 2 more answers
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