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2 years ago

Which of the following is a chemical property?

Chemistry

2 answers:

ad-work [718]2 years ago

6 0

The first one is D hope it helps!

denis23 [38]2 years ago

6 0

First one is D. Second is A. Get rekt Connections Academy

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What is the wavelength of a wave having a frequency of 3.76x10^14

choli [55]

Answer:

3.76 x 1014 s-1? λ = c/ν = 3.00 x 108 m/s = 7.98 x 10-7 m 3.76 x 1014 s-1.

Explanation:

hope i helped btw i am breanna plzz mark me brainliest

4 0

3 years ago

Rasheed calculates that his chemical reaction should produce 4 moles of product, but when he does the experiment, he gets only 3

Brut [27]

Answer:

The answer to your question is 75%

Explanation:

Data

Theoretical production = 4 moles

Experimental production = 3 moles

Percent yield = ?

Formula

$Percent yield = \frac{Experimental production}{Theoretical production} x 100$

Substitution

$Percent yield = \frac{3}{4} x 100$

Result

Percent yield = 75 %

8 0

3 years ago

An object has a velocity of 8m/s and a kinetic energy of 480 j what is the mass of the object

MariettaO [177]

Kinetic energy=Ek
Ek=(1/2)mv²
Ek=480 J
v=8 m/s
mass=?

Ek=(1/2)mv²
480 J=(1/2)m(8 m/s)²
480 J=(32 m²/s²) m
m=(480 J)/(32 m²/s²)=15 kg

answer: the mass of the object is 15 kilograms.

3 0

2 years ago

A student placed equal volumes of honey and of water in two, identical, open dishes, and left them at room temperature for 8 hou

Ahat [919]

Answer: Honey has a much lower vapor pressure than pure water has. So, pure water evaporates at a much higher rate.

Explanation:

8 0

2 years ago

Read 2 more answers

One of the radioactive isotopes used in medical treatment or analysis is chromium-51. The half-life of chromium-51 is 28 days. H

Goryan [66]

Answer : The time required for decay is, 84 days.

Explanation :

Half-life of chromium-51 = 28 days

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{28\text{ days}}$

$k=0.0248\text{ days}^{-1}$

Now we have to calculate the time required for decay.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = time taken by sample = ?

a = let initial activity of the sample = 100

a - x = amount left after decay process = 12.5

Now put all the given values in above equation, we get

$t=\frac{2.303}{0.0248}\log\frac{100}{12.5}$

$t=83.9\text{ days}\approx 84\text{ days}$

Therefore, the time required for decay is, 84 days.

7 0

3 years ago