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Alekssandra [29.7K]
3 years ago
10

How will the addition of water affect the acidity of a highly acidic solution having pH 2?. A) There will be a slight decrease i

n the pH value. B) There will be a slight increase in the pH value. C) The pH value will remain constant.
Chemistry
1 answer:
zvonat [6]3 years ago
3 0
The addition of water to the solution slightly decreases the concentration of the hydrogen ion in the solution. As pH is dependent to this, it will also change. The decrease in the concentration will increase the pH value. Thus, the answer is letter B. 
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How far is the earth from the sun?
GalinKa [24]
The answer should be 1 AU as it’s just about close to the number of miles from earth to sun.
Earth to sun in miles is -92.96
1 AU is- 92955807.3
5 0
3 years ago
The electron configurations of five different elements are shown below. which of these elements is expected to have the largest
ipn [44]
Missing question:

(a) 1s2 2s2 2p6 3s1
(b) 1s2 2s2 2p6 3s2
(c) 1s2 2s2 2p6 3s2 3p1

(d) 1s2 2s2 2p6 3s2 3p4

(e) 1s2 2s2 2p6 3s2 3p5

Answer is: a) 1s²2s²2p⁶3s¹ (sodium).

Sodium have the largest second ionization energy, because when he lost one electron(first ionization energy), he have stable electron configuration of noble gas neon (1s²2s²2p⁶), so sodium do not need to lost second electron, because he will have unstable electron configuration.

7 0
3 years ago
The question:A new grill has a mass of 30.0 kg. You put 2.0 kg of charcoal in the grill. You burn all the charcoal and the grill
Maurinko [17]

Answer:- Molar mass of CO_2 .

Solution:- It is a stoichiometry problem. Mass of the grill is 30.0 kg and the mass after burning the grill is also 30.0 kg. It means all the charcol is burned and the gas is given off.

2.0 kg of charcol are converted to grams which is 2000 g. Since charcol is pure solid carbon, the grams are divided by the atomic mass of carbon which is 12.

The combustion equation of charcol is written as:

C(s)+O_2(g)\rightarrow CO_2(g)

From this balanced equation, there is 1:1 mol ratio between charcol and carbon dioxide. So, the moles of carbon dioxide gas formed are equivalent to the moles of charcol. To convert the moles of carbon dioxide to grams we multiply the moles by it's molar mass.

Carbon dioxide has one carbon and two oxygen atoms so it's molar mass = 12 + 2(16) = 12 + 32 = 44

So, 44 is the molar mass of carbon dioxide and above calculations clearly shows how and where we get this.

5 0
3 years ago
2. Consider the reaction 2NO(g) + O2(g) → 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is r
vredina [299]

Answer :

(a) The rate of NO_2 formed is, 0.066 M/s

(b) The rate of O_2 formed is, 0.033 M/s

Explanation : Given,

\frac{d[NO]}{dt} = 0.066 M/s

The balanced chemical reaction is,

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

The rate of disappearance of NO = -\frac{1}{2}\frac{d[NO]}{dt}

The rate of disappearance of O_2 = -\frac{d[O_2]}{dt}

The rate of formation of NO_2 = \frac{1}{2}\frac{d[NO_2]}{dt}

As we know that,

\frac{d[NO]}{dt} = 0.066 M/s

(a) Now we have to determine the rate of NO_2 formed.

\frac{1}{2}\frac{d[NO_2]}{dt}=\frac{1}{2}\frac{d[NO]}{dt}

\frac{d[NO_2]}{dt}=\frac{d[NO]}{dt}=0.066M/s

The rate of NO_2 formed is, 0.066 M/s

(b) Now we have to determine the rate of molecular oxygen reacting.

-\frac{d[O_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}

\frac{d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s

The rate of O_2 formed is, 0.033 M/s

6 0
3 years ago
Where do the elements come from? select all that apply?*
Naily [24]

Answer:

the answer of your question is below:

Explanation:

decay

8 0
3 years ago
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