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faust18 [17]
3 years ago
15

Where do the elements come from? select all that apply?*

Chemistry
1 answer:
Naily [24]3 years ago
8 0

Answer:

the answer of your question is below:

Explanation:

decay

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Which of the following orbitals is the largest in size?
tamaranim1 [39]
The answer would be B.
3 0
3 years ago
If the principal quantum number is n = 3, what are the name(s) of the subshells?
Ede4ka [16]

The name(s) of the subshells are s,p and d

<h3>Further explanation</h3>

Each orbital in an atom consists of 4 quantum numbers  

n is the principal quantum number.  

l is the angular momentum / azimuthal quantum number  

ml, the magnetic quantum number  

ms, the electron-spin quantum number  

Value of n: positive integer  

value of l: s = 0, p = 1, d = 2, f = 3 , ..(n-1)

ml value: between -l to + l  

ms value: +1/2 or -1/2  

n=3, then the possible value of l is a maximum of n-1 = 3-1 = 2

So the value of subshells = 0,1 and 2

8 0
3 years ago
Read 2 more answers
Fill in the blanks to complete the hypothesis for this lab experiment.
AleksandrR [38]

Answer:

If NaOH of a known concentration neutralizes HCl of an unknown concentration, then you can use the volumes to determine the concentration of the HCl, because, at the equilibrium point, the number of moles of HCl equals the number of moles of NaOH.

Explanation:

I just finished the assignment.

7 0
3 years ago
2c2h2(l) 5o2(g) yeild 4co2(g) 2h2o(g) if the acetylene tank contains 37.0 mol of c2h2 and the oxygen tank contains 81.0 mol of o
Murrr4er [49]

2C2H2(l)  +5O2(g)→ 4Co2(g)  + 2H2O

The   limiting  reactant  for reaction above is O2


<u><em>explanation</em></u>

 The limiting reagent is determined using mole ratio  of both reactant.

 that  is the  mole ratio  of  C2H2:O2  which is  2:5 .

 The mole ratio above  implies  that 37.0 mole  of C2H2   needs  37.0 moles  x5/2=92  moles of  O2.


<em>Since the available moles of O2  was 81.0 mole  and 92  moles  are  required to completely  react with  C2H2</em><em> ,</em> <u>O2   is  the limiting reagent.</u>

6 0
3 years ago
Starting with acetylene and bromoethane, show how you would use reagents from the table to synthesize 3-hexanone.
Jobisdone [24]

solution:

A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg

 Starting by hitting acetylene with NaNH2 to deprotonate, this C-- will attack the C connected to the Br Sn2 style to lengthen the chain by two carbons.  

Do this same thing again with the other CH of the acetylene and another bromoethaneto get a six carbon chain, namely, 3-hexyne.  

Now, reduce the alkyne to an alkene via H2/Pd/C, and that gives 3-hexene.  


3 0
3 years ago
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