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Cloud [144]
3 years ago
13

Choose the appropriate volumetric device to use for each of the volume measuring applications.

Chemistry
1 answer:
Oksanka [162]3 years ago
4 0

Answer:

1. Beaker and Flask: These two volumetric devices are used to make coarse measurements of volume. These devices have graduated volume measurements marked on the side if the beaker and flask. The beaker and flask have a 5% accuracy.

2. Graduated Cylinder: More accurate than beakers and flask, with a 1% accuracy. Graduated cylinder are transparent with finely divided graduations. Their size vary from 5mL to 200mL.

3. Burets: These are cylindrical glassware with a valve at the bottom (commonly called a “stopcock”). They also have graduations on the side for accurate reading, and they have a 0.01mL accuracy.

4. Pipets: 12-24 inches long slender tubes, that measure predetermined volume. Mohr pipets are volumetric glassware pipets with graduations used to measure odd or fractional volumes to be provided. They have a 0.02mL accuracy. There are three types of pipets: air-displacements; positive-displacement; and the dispenser pipet.  

Explanation:

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What is the emperical formula of a compound containing 40.1% carbon and 6.6% hydrogen​
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Answer:

CH₂

Explanation:

Given parameters:

Percentage composition:

          Carbon  = 40.1%

          Hydrogen  = 6.6%

Unknown:

Empirical formula of the compound  = ?

Solution:

The empirical formula of a substance is its simplest formula.

 Elements                             Carbon                             Hydrogen

Percentage

Composition                           40.1                                     6.6

Molecular mass                        12                                         1

Number of moles                  40.1/12                                  6.6/1

                                                3.342                                    6.6

Divide through by

the smallest                         3.342/3.342                           6.6/3.342

                                                      1                                        2

So the empirical formula of the compound is CH₂

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