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8090 [49]
3 years ago
8

How can I find a unit rate when given a rate?

Mathematics
1 answer:
Butoxors [25]3 years ago
7 0
You would divide the rate
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Which of the following is equal to the rational expression when x ≠ -2 or 3?
ASHA 777 [7]

Answer:

the answer is A

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
!!!! PLEASE HELP !!!!!!
Keith_Richards [23]

Answer:

i got -8 but the closest is -7 so u can tried that

Step-by-step explanation:

5 0
3 years ago
1 point
galina1969 [7]

Answer:

(B) 20

Step-by-step explanation:

Let small puppet be represented by-----------------s

Let large puppet be represented by-----------------l

Total number of puppets expression will be: s+l =25---------a

The expression for total costs will be : 1$ s + $2l=$30-------b

Equation a can be written as; s= 25-l ------------c

Use equation c in equation b as

$1( 25-l )+$ 2l = $30

25-l + 2l = 30

25+l =30

l= 30-25 =5

l, large puppets = 5

s, small puppets = 25-5 = 20

Answer choice A is incorrect because 25 is the total number of all puppets

Answer choice C and D are incorrect because the numbers are less that that of small puppets.

3 0
3 years ago
What are the potential solutions of log4x+log4(x+6)=2?
lions [1.4K]

The potential solutions of log_4x+log_4(x+6)=2 are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

  • Product Rule for Logarithms - log_{b}(a*c)=log_{b}a+log_{b}c
  • Quotient Rule for Logarithms - log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c
  • Power Rule for Logarithms - log_{b}(a^c)=c*log_{b}a

The exercise asks the potential solutions for  log_4x+log_4(x+6)=2. In this expression you can apply the Product Rule for Logarithms.

                                  log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0

Now you should solve the quadratic equation.

 

 Δ=b^2-4ac=36-4*1*(-16)=36+64=100. Thus, x will be x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}. Then:

x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8

The potential solutions  are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

4 0
2 years ago
Need help on question hurry
Hoochie [10]

Answer: C

Step-by-step explanation: it is c trust me

7 0
2 years ago
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