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8090 [49]
2 years ago
8

How can I find a unit rate when given a rate?

Mathematics
1 answer:
Butoxors [25]2 years ago
7 0
You would divide the rate
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Evaluate the expression when p= -24 and q = 4.
Talja [164]

(2 \times  - 24) \div  - 4
which comes out as 12
3 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
Solve xy - 3 = k solve for x
ladessa [460]

Answer:

x=(k+3)/y

Step-by-step explanation

First, we simplify by adding 3 to both sides of the equation

xy-3+3=k+3

Now it's xy=k+3

To get x we divide both sides by y

So x=(k+3)/y

3 0
3 years ago
Read 2 more answers
At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist headi
gizmo_the_mogwai [7]
----------------------------------------------------------------------------------------------
Find the duration
----------------------------------------------------------------------------------------------
Time : 9:00am to 10:15am 
Duration: 1hour 15 mins or 1.25hours

----------------------------------------------------------------------------------------------
Find difference in distance travelled between the two cyclists.
----------------------------------------------------------------------------------------------
Difference in speed = 6km/h
1 hour = 6 km
1.25 hours = 7.5km

----------------------------------------------------------------------------------------------
Find the distance the cyclist traveled
----------------------------------------------------------------------------------------------
42.5 - 7.5 = 35km
35km ÷ 2 = 17.5km

The slower cyclist traveled 17.5 km in the 1.25 hours

17.5 + 7.5 = 25 km

The faster cyclist traveled 25km in the 1.25 hours

----------------------------------------------------------------------------------------------
Find the speed of the slower cyclist
----------------------------------------------------------------------------------------------
1.25 hour = 17.5 km
1 hour = 17.25 ÷ 1.25
1 hour = 14km

The cyclist was traveling at 14km/h

----------------------------------------------------------------------------------------------
Find the speed of the faster cyclist
----------------------------------------------------------------------------------------------
1.25 hour = 25km
1 hour = 25 ÷ 1.25
1hour = 20 km

The cyclist was traveling at 20km/hour

----------------------------------------------------------------------------------------------
Answer: The speed were 14km/h and 20 km/h
----------------------------------------------------------------------------------------------

8 0
3 years ago
Read 2 more answers
Helppp me plsssssssss<br><br>​
Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

  • \sf \:\:\:\:\:\:\:\:\:\:x_{k}=35
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k}=50
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42
  • \sf \:\:\:\:\:\:\:\:\:\:h=5

{\bf \:\: {By\:using\:the\: formula}} \\ \\

\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\

\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\

\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\

{\large{\frak{\pmb{\underline{Additional\: information }}}}}

MODE

  • Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

  • In a frequency distribution the class having maximum frequency is called the modal class.

{\bf{\underline{Formula\:for\: calculating\:mode:}}} \\

{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\

Where,

\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.

\small \blue{ \bigstar}\sf \: f_{k}=frequency\:of\:the\:modal\:class

\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class

\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class

\small \purple{ \bigstar}\sf \: h= width \:of\:the\:class\:interval

7 0
3 years ago
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