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lubasha [3.4K]
3 years ago
7

Why is it necessary to take a person’s weight into account when a doctor prescribes medications?

Chemistry
1 answer:
Nonamiya [84]3 years ago
4 0

I think to see if the medication causes weight gain or weight loss. I just got prescribed a medication that can cause either of those and I had to be weighed.

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Group 2A metal oxides react with water to produce hydroxides. When 35.55 g of CaO are placed into 125 mL of water (d= 1.000 g/mL
Vika [28.1K]
Answer is: mass of calcium hydroxide is 46.98 grams.
Balanced chemical reaction: CaO + H₂O → Ca(OH)₂.
m(CaO) = 35.55 g.
n(CaO) = m(CaO) ÷ M(CaO).
n(CaO) = 35.55 g ÷ 56 g/mol.
n(CaO) = 0.634 mol; limiting reactant.
m(H₂O) = 125 mL · 1.000 g/mL.
m(H₂O) = 125 g.
n(H₂O) = 125 g ÷ 18 g/mol.
n(H₂O) = 6.94 mol.
From chemical reaction: n(CaO) : n(Ca(OH)₂) = 1 : 1.
n(Ca(OH)₂) = 0.634 mol.
m(Ca(OH)₂) = 0.634 mol · 74.1 g/mol = 46.98 g.
5 0
3 years ago
In 25 words or fewer, what do you think a scientist would want to explain about this soda?
Gnesinka [82]

Answer:

This soda is brown, sweet, has high carbonation, and is about 200 calories when consumed.

Explanation:

:)

8 0
3 years ago
Magnesium reacts with hydrochloric acid (HCl) as follows. Mg(s) + 2HCl(aq) -->MgCl(2)+H(2)(g) How many milliliters of hydroge
max2010maxim [7]
We are given the number of moles of solid magnesium supplied for the reaction which is 0.02 moles while hydrochloric acid is supplied in excess thus we can say that the reaction proceeds to completion. Calculation is as follows:

0.020 mol Mg ( 1 mol H2 / 1 mol Mg ) = 0.020 mol H2 gas is produced

To convert the number of moles to volume, we use the conditions at STP of 1 mol of a substance is equal to 22.4 L. Thus,

0.020 mol H2 (22.4 L / 1 mol) (1000 mL / 1 L) = 448 mL
5 0
4 years ago
Answer will mark bl plz
lesya692 [45]

Answer:

A

Explanation:

The mallet transfers kinetic energy, then that energy is transferred to the orange ball, then the purple ball, thus making the purple ball move

3 0
4 years ago
A 845 mL NaCl solution is diluted to a volume of 1.19 L and a concentration of 6.00 M . What was the initial concentration? Expr
marysya [2.9K]

The initial concentration was 8.45M

Step 1: Given data

Initial concentration (C₁): ?

Initial volume (V₁): 635 mL = 0.845 L

Final concentration (C₂): 6.00 M

Final volume (V₂): 1.19 L

Step 2: Calculate the initial concentration

We have a concentrated NaCl solution and we want to prepare a diluted one. We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₁ = C₂ × V₂  / V₁

C₁ = 6.00 M × 1.19 L  / 0.845 L

C₁ = 8.45 M

Thus, The initial concentration was 8.45M

Learn more about concentration here:

brainly.com/question/10725862

#SPJ4

7 0
2 years ago
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