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Phoenix [80]
3 years ago
15

If I use the answers from here wouldn't that come up as a high % plagiarism ??

Chemistry
2 answers:
damaskus [11]3 years ago
6 0

Answer:

No

Explanation:

My sister uses this all the time and it is perfectly safe

Katyanochek1 [597]3 years ago
4 0

Answer:

no

Explanation:

as long as you change it up a little and word it to look like your own

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n200080 [17]

Answer:

hvhvfhvfhbvfhvbbbbbbb

Explanation:

5 0
3 years ago
Read 2 more answers
A van moves with a constant speed
Kitty [74]

Answer:

1.5 hours or 90 minutes

Explanation:

Velocity = d/t

V = 64 mi / hour or 96 mi / 9 min OR 16 mi / 15 min

D = 96 miles

Velocity * Time = Distance

Time = Distance / Velocity

T = 96 mi / 64 mi / hour

96 / 64 = 1.5 mi per hour

T = 1.5 hours or 90 minutes

4 0
3 years ago
if you were to engineer an everyday solution for conserving water which activity do you think would be the most impactful ?
Ugo [173]
If you were to engineer an everyday solution for conserving water which activity do you think would be the most impactful ?
7 0
2 years ago
What is the molarity of a solution that contains 1000.0 mg of AgNO3 that has been dissolved in 500 mL of water
Vaselesa [24]

0.012moldm⁻³

Explanation:

Given parameters:

Mass of AgNO₃  = 1000mg

Volume of water = 500mL

Unknown:

Molarity of solution  = ?

Solution:

The molarity of a solution is the number of moles of a solute dissolved in volume of solvent.

 Molarity = \frac{xnumber of moles}{Volume}

 

Number of moles of AgNO₃  = ?

   Number of moles = \frac{mass}{molar mass}

Molar mass of AgNO₃ = 108 + 14 + 3(16) = 170g/mol

   convert mass to g;

      1000mg = 1g

 Number of moles  = \frac{1}{170}  = 0.00588moles

   convert the given volume to dm³;

       1000mL  = 1dm³;

        500mL = 0.5dm³

Now solve;

  Molarity = \frac{0.00588}{0.5}  = 0.012moldm⁻³

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

4 0
3 years ago
Calculate the concentration in % (m/m) of a solution containing 30.0g of mgcl2 dissolved in 270.0g of h20
qaws [65]
As the question tells you, you need to use the formula

% mass= mass of solute/ mass of solution x 100

mass solute= 30.0 g
mass of solution= 30.0 + 270.0= 300.0 g

% mass= 30.0/ 300.0 x 100= 10%

answer is B
4 0
3 years ago
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