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bogdanovich [222]
3 years ago
7

What is the solution of the system of equations? y = –2x + 8 y = x – 4

Mathematics
2 answers:
Citrus2011 [14]3 years ago
8 0

Answer:

ur answer is (4,0) gradpoint

Step-by-step explanation:

12345 [234]3 years ago
4 0
<span>y = –2x + 8 
y = x – 4

We can use substitution.
-2x+8 = x-4
3x=12
x=12/3
x=4

</span>y = x – 4
<span>y=4-4=0
y=0

Solution of the system x=4,y=0,
it can be written as (4,0).

</span>
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Please help!!! I need someone to use some brain power
olya-2409 [2.1K]

Answer:

  • r = 4, s = 3, t = 5

Step-by-step explanation:

<u>Solving quadratic equation:</u>

  • 5x² - 8x + 5 = 0
  • x = (-b ± √b²-4ac)/2a
  • x = (8 ± √8²-4*5*5)/2*5
  • x = (8 ± √64-100)/10
  • x = (8 ±√-36)/10
  • x = (8 ± 6i)/10
  • x = (4 ± 3i)/5

x = (r ± si)/t

r = 4, s = 3, t = 5

3 0
3 years ago
What is the solution of 2x^2+8=x^2-16
AfilCa [17]

Answer:

x = -12

Step-by-step explanation:

2x^2 + 8 = x^2 - 16

2x + 2x + 8 = x + x - 16

4x + 8 = 2x - 16

-2x        -2x

2x + 8 = -16

      -8     -8

2x = -24

----   ------

2        2

x = -12

8 0
3 years ago
Please hElp!! I don't know how to do this!!!
pishuonlain [190]
150 more male bats need to be tagged

if you want 2/5 to be female you divide the 260 (<160+100) by 2 to get 130
then you multiply 130 by 3 to get the total amount of male bats that need to be tagged
130*3=390
then you subtract 240 from the 390 to find out how many more bats need to be tagged
390-240=150
7 0
3 years ago
Geometry help! Please prove the following is a square with full explanation, I'm really lost.
Hoochie [10]

We have to show that this is a square, meaning all the sides are perpendicular and the same distance.  

A(3,4), B(2,-2), C(-4,-1), D(-3,5)

For each side we calculate the squared distance and the slope.  We don't have to bother to take the square root.  We'll subtract the points first because that difference, called the direction vector, goes into both the calculation of the slope and of the distance.

AB=B-A=(2 - 3, -2 - 4) = (-1, -6).   slope=-6/-1=6  AB²=(-1)²+(-6)²=37

BC=C-B=(-6, 1).  slope=1/-6=-1/6.   BC²=(-6)²+1²

CD=D-C=(1, 6).   slope=6/1=6    CD²=1²+6²=37

DA=A-D=(6,-1)   slope=-1/6     DA²=37

We see the negative reciprocal slopes, alternating between 6 and -1/6, indicating perpendicular sides.  We see they all have squared distance 37.  Equal perpendicular sides proves its a square.

If we do these problems enough we learn:  There's no point taking the square root.  In fact, there's really no point computing the slopes and the squared distances; we can see it's a square from the pattern of the direction vectors of the sides:  (-1, -6) (-6, 1) (1, 6) (6,-1)

5 0
3 years ago
What are the possible numbers of positive, negative, and complex zeros of f(x)=x^6-x^5-x^4+4x^3-12x^2+12?
Vadim26 [7]
f(x)=x^6-x^5-x^4+4x^3-12x^2+12\\\\12:\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm12\}\\1:\{\pm1\}\\\\Answer:\boxed{\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm12\}}
8 0
3 years ago
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