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klemol [59]
3 years ago
12

2+4x=2y/w solve for x

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

x = y/2w - 1/2

Step-by-step explanation:

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Determine the length of the model.<br> -60 ft-<br> 1 in. = 8 ft<br> =
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Length of the model = 11.6 inch
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3 years ago
Tony is 5.75 feet tall. Late one afternoon, his shadow was 8 feet long. At the same time, the shadow of a nearby tree was 32 fee
dangina [55]

the height of the tree is 23 feet .

<u>Step-by-step explanation:</u>

Here we have , Tony is 5.75 feet tall. Late one afternoon, his shadow was 8 feet long. At the same time, the shadow of a nearby tree was 32 feet long. We need to find Find the height of the tree. Let's find out:

According to question , Tony is 5.75 feet tall. Late one afternoon, his shadow was 8 feet long . Let the angle made between Tony height and his shadow be x . Now , At the same time, the shadow of a nearby tree was 32 feet long. Since the tree is nearby so tree will subtend equal angle of x. Let height of tree be y , So

⇒ Tanx=\frac{y}{32}

But , From tony scenario

⇒ Tanx=\frac{5.75}{8}

Equating both we get :

⇒ \frac{y}{32}  = \frac{5.75}{8}

⇒ y=\frac{5.75(32)}{8}

⇒ y=23ft

Therefore , the height of the tree is 23 feet .

3 0
3 years ago
Suppose that the probability that your mail is delivered before 2pm is .90. What is the probability that your mail will be deliv
Elden [556K]
1. The probability that your mail is delivered before 2 pm is 0.9, so the probability that the mail is delivered at 2 pm or after 2 pm (so not before 2 pm) is 1-0.9=0.1.

Remark: 0.9=9/10=90/100=90%, and 0.1 is 10%

2. Probability of the mail being delivered before 2 pm for 2 consecutive days is 
\frac{90}{100}*  \frac{90}{100}= \frac{9}{10}*  \frac{9}{10}= \frac{81}{100}=0.81

3. take a look at the picture attached, the tree diagram is another method we could use. 

4 0
3 years ago
a contractor needs to purchase 500 bricks. the dimensions of each brick are 5.1 cm by 10.2 by 20.3 cm, and the density of each b
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No, the trailer cannot hold the weight of the bricks. It is beyond the 900kg capacity of the trailer. The total weight of the bricks is 1,013.77 kilograms. The total weight was derived from getting the volume of the brick (0.051m x 0.102m x 0.203m), then multiplying the volume to the density of each brick (1.056 x 10^3m^3 x 1920kg/m^3). The weight of each brick is 2.03kg. Lastly, multiply the total number of bricks to the weight of each brick to get the total weight.
5 0
3 years ago
If u help I’ll give u brainliest but please give correct answer
Black_prince [1.1K]

Answer:

here is no question sorry

4 0
3 years ago
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