Length of the model = 11.6 inch
the height of the tree is 23 feet .
<u>Step-by-step explanation:</u>
Here we have , Tony is 5.75 feet tall. Late one afternoon, his shadow was 8 feet long. At the same time, the shadow of a nearby tree was 32 feet long. We need to find Find the height of the tree. Let's find out:
According to question , Tony is 5.75 feet tall. Late one afternoon, his shadow was 8 feet long . Let the angle made between Tony height and his shadow be x . Now , At the same time, the shadow of a nearby tree was 32 feet long. Since the tree is nearby so tree will subtend equal angle of x. Let height of tree be y , So
⇒ 
But , From tony scenario
⇒ 
Equating both we get :
⇒ 
⇒ 
⇒ 
Therefore , the height of the tree is 23 feet .
1. The probability that your mail is delivered before 2 pm is 0.9, so the probability that the mail is delivered at 2 pm or after 2 pm (so not before 2 pm) is 1-0.9=0.1.
Remark: 0.9=9/10=90/100=90%, and 0.1 is 10%
2. Probability of the mail being delivered before 2 pm for 2 consecutive days is

3. take a look at the picture attached, the tree diagram is another method we could use.
No, the trailer cannot hold the weight of the bricks. It is beyond the 900kg capacity of the trailer. The total weight of the bricks is 1,013.77 kilograms. The total weight was derived from getting the volume of the brick (0.051m x 0.102m x 0.203m), then multiplying the volume to the density of each brick (1.056 x 10^3m^3 x 1920kg/m^3). The weight of each brick is 2.03kg. Lastly, multiply the total number of bricks to the weight of each brick to get the total weight.
Answer:
here is no question sorry