Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
x=10
Step-by-step explanation:
Let the number = x
∴ 2x/5=4
∴2x=5*4
∴2x=20
∴x=20/2
∴x=10
Hope it helps you!
Mark as brainliest if you like it
Answer:
Ox=4
Step-by-step explanation:
expand he equation
x²+8x-48=0
using substitution method (of the options)
4 substituted as X eliminates all an results to zero
16+32-48=0
please mark brainliest
p= 1/7
Alright, so first, you need to flip the equation.<span><span>It will turn into p+<span>4/7</span></span>=<span>5/7
Next, you want to get the variable by itself so you need to subtract 4/7 from both sides. 5/7-4/7=1/7
p=1/7</span></span>
Answer:
x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3
Step-by-step explanation:
Let's solve for x.
3x2+y2=9
Step 1: Add -y^2 to both sides.
3x2+y2+−y2=9+−y2
3x2=−y2+9
Step 2: Divide both sides by 3.
3x^2/3= -y^2+9/3
x^2=-1/3 y^2 +3
x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3
Hope it helped!
