Answer:
False, isotopes have different occurrence percentages, so the changes are different.
Explanation:
Hello,
In this case, since it is false that the isotopes of all the elements can be found with the same chance (occurrence) we can consider the following facts:
1. Carbon atom has two major occurring isotopes: C-12 (98.93%) and C-13 (1.07%).
2. Bromine atom has two major occurring isotopes: Br-79 (50.69%) and Br-81 (49.31%).
3. Calcium has four major occurring isotopes: Ca-40 (96.941%), Ca-42 (0.647%), Ca-43 (0.135%) and Ca-44 (2.086%).
Which show us that the chances of finding any isotope differ among elements.
Regards.
"Work done by a constant force on an object is the product of the force and the distance moved by the object in the direction of the force" -textbook
There is work done ONLY if the direction of the force and the direction the item is moving are the same. In figure A, the direction of the force (the lifting) is upwards (defying gravity), and the book is moving upwards, so work is done. In figure B, the force is still moving upwards (the person is carrying the books) but the book is moving to the right, so there is NO work done.
Answer:
turgor pressure can be done in a lab or a self test.
turgor pressure is key to the plant’s vital processes. It makes the plant cell stiff and rigid. Without it, the plant cell becomes flaccid. Prolonged flaccidity could lead to the wilting of plants.
Turgor pressure is also important in stomate formation. The turgid guard cells create an opening for gas exchange. Carbon dioxide could enter and be used for photosynthesis. Other functions are apical growth, nastic movement, and seed dispersal.
Explanation:
- salt is bad for turgor pressure.
- Turgidity helps the plant to stay upright. If the cell loses turgor pressure, the cell becomes flaccid resulting in the wilting of the plant.
- The wilted plant on the left has lost its turgor as opposed to the plant on the right that has turgid cells.
You can split the process in two parts:
1) heating the liquid water from 10.1 °C to 25.0 °C , and
2) vaporization of liquid water at constant temperature of 25.0 °C.
For the first part, you use the formula ΔH = m*Cs*ΔT
ΔH = 30.1g * 4.18 j/(g°C)*(25.0°C - 10.1°C) = 1,874 J
For the second part, you use the formula ΔH = n*ΔHvap
Where n is the number of moles, which is calculated using the mass and the molar mass of the water:
n = mass / [molar mass] = 30.1 g / 18.0 g/mol = 1.67 mol
=> ΔH = 1.67 mol * 44,000 J / mol = 73,480 J
3) The enthalpy change of the process is the sum of both changes:
ΔH total = 1,874 J + 73,480 J = 75,354 J
Answer: 75,354 J
Answer:) is related to the change in free energy of the reaction--d
Explanation:
For any reaction that is taking place at any moment the change in Gibbs Free Energy is related to the reaction quotient as
ΔG=ΔG⁰+RTlnQ
where R-Universal Gas Constant, T- Temperature in Kelvin, Q is the reaction quotient
Now when the system is in equilibrum, ΔG⁰ which is the standard Gibb's Free Energy,is then defined as
ΔG⁰=−RTlnK ,
where K is the equilibrium constant. because ΔG becomes 0 and reaction quotient Q = K
The equilibrum constant is related to the change in free energy of the reaction.
because when ΔG is negative, the value of K is high which leads to a spontaneous. reaction
when ΔG is positive, the value of K is low, which leads to a spontaneous. reaction in the opposite direction.
