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stellarik [79]
2 years ago
15

Find an equation of the tangent line to the curve at the given point. y = 3x3 â x2 + 3, (2, 23)

Mathematics
1 answer:
klasskru [66]2 years ago
5 0
IDK so so so sorry i am not fameluar with this
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Answer:

7

Step-by-step explanation:

Pythagorean Theorem:

25^2=24^2+x

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Find the value of each variable in the parallelogram
melomori [17]

Alright.

For 7, you'll want to put congruent sides equal to each other, assuming they are parallelograms. So, you'll get the two equations:

3x+2=23

2y-7=9

Solve using GEMDAS/PEMDAS, and you'll get these answers.

3x+2=23

3x=21

x=7

2y-7=9

2y=2

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For 8, you'll want to do the exact same thing, formatting the numbers to equal each other. You'll get these two equations:

3y+5=14

2x-5=17

Solving them would make:

3y+5=14

3y=9

y=3

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2x=22

x=11

For 9, you have to remember that the angle opposite of one angle in a defined parallelogram are congruent. Thus:

130=2h

5k=50

solve them and you get

h=65

k=10

___________________________________________

Hope that helped. Good luck.

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