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PilotLPTM [1.2K]
4 years ago
11

Sheldon says that the expression 8(4x - 2)=32x-16

Mathematics
1 answer:
Arte-miy333 [17]4 years ago
8 0

Answer:

That is correct

Step-by-step explanation:

distribute the 8

8*4x = 32x

8*2 = 16

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What’s the value of x? <br> y= 5x + 9<br> y= -x + 3
ser-zykov [4K]

Answer:

x=-1 y=4                                (-1,4)

Step-by-step explanation:

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The equation y=1/3xis the boundary line for the inequality y&gt;1/3x. Which sentence describes the graph of the inequality
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If th<span>e equation y=1/3x is the boundary line for the inequality y>1/3 x, then the solution set is illustrated by shading the area ABOVE the line y=(1/3)x.</span>
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3 years ago
Find each missing angle <br> Please
-BARSIC- [3]

Answer:

m<1=61

m<2=40

m<3=60

m<4=80

m<5=100

Step-by-step explanation:

180/3=60

180/9=20

20x2=40

20x4=80

20x3=60

59+60=119

180-119=61

180-80=100

7 0
3 years ago
What is the equation for the line described in #9And #10?
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2 years ago
Suppose that X has a discrete uniform distribution on the integers 0 through 9. Determine the mean, variance, and standard devia
Anna35 [415]
With 10 integers available, X has PMF

\mathbb P(X=x)=\begin{cases}\dfrac1{10}&\text{for }0\le x\le9,x\in\mathbb Z\\\\0&\text{otherwise}\end{cases}

We're interested in the statistics of the new random variable Y=5X. To do this, we need to know the PMF for Y. This isn't too hard to find.

\mathbb P(Y=y)=\mathbb P(5X=y)=\mathbb P\left(X=\dfrac y5\right)

Since the PMF for X gives a value of \dfrac1{10} whenever x is an integer between 0 and 9, it follows that \dfrac y5 must also be an integer for the PMF to give the identical value of \dfrac1{10}. This means

\mathbb P(Y=y)=\begin{cases}\dfrac1{10}&\text{for }y\in\{0,5,\ldots,45\}\\\\0&\text{otherwise}\end{cases}

Now the mean (expectation) is

\mathbb E(Y)=\displaystyle\sum_yy\mathbb P(Y=y)=\frac1{10}\sum_{y\in\{0,\ldots,45\}}y
\mathbb E(Y)=\dfrac{225}{10}=22.5

The variance would be

\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2
\mathbb V(X)=\displaystyle\sum_yy^2\mathbb P(Y=y)-\mathbb E(Y)^2
\mathbb V(X)=\displaystyle\frac1{10}\sum_{y\in\{0,\ldots,45\}}y^2-\left(\frac{225}{10}\right)^2
\mathbb V(X)=\dfrac{7125}{10}-\dfrac{50625}{100}=206.25

The standard deviation is the square root of the variance, so you have

\sqrt{\mathbb V(X)}=\sqrt{206.25}\approx14.3614
8 0
3 years ago
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