Answer:
Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
Step-by-step explanation:
4c + 6a ≤ 120:
You can set up the inequality 4c + 6a ≤ 120, because it takes 4 hours to build per child bike (c) and 6 hours to build an adult bike (a), all together this time cannot surpass 120 hours. That is why you use the 'less than or equal to' sign.
4c + 4a ≤ 100:
You can then set up the inequality 4c + 4a ≤ 100, because it takes 4 hours to test a child bike (c) and 4 hours to test an adult bike (a). Since 100 hours is the max amount of time they can use to test out bikes, you will use the 'less than or equal to' sign.
4(5) + 6(15) = 20 + 90 = 110. 110 is less than 120
4(5) + 4(15) = 20 + 60 = 80. 80 is less than 100
Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
Answer:
Move the dot at the axis one to the left and one down move the other dot to (7,0)
Step-by-step explanation:
Find the dot at the origin (0,0)
Move it to (-1,-1) which is one unit to the left and one unit down.
Select other dot and place it at (7,0)
Click submit
Frank = F
Sue = S
John = J
F=3*S
F = J+15
S = J-1
If you want to find Frank's age, then his age would be equivalent to John's plus 15 years.
A.-Would not work because Frank is three times Sue's age, not John's (left hand side of the equation).
B.-Notice that the right hand side of the equation is equivalent to Sue's age, which we know is John-1, however it is currently written to be "three times Sue's age minus one" which would give us John's age, plus two more years than his actual age on the left hand side.
C.-Frank's age is equal to John's plus fifteen (right side of the equation) and Frank is equal to Sue's age times 3. But, if Sue is in terms of Johns, then Sue's age is John's minus one. Therefore, Frank's age is equal to three times Sue's age of John minus one, which is the left-hand side of our equation.
Therefore C is the answer. C: