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poizon [28]
4 years ago
9

A sound wave traveling downward with a speed of about 4,000 m/s suddenly slows to 1,500 m/s not far below the earth’s surface. w

hat has the sound wave most likely encountered?
Physics
2 answers:
krok68 [10]4 years ago
5 0

Answer: an underground lake

Explanation:

I took the test

Ksivusya [100]4 years ago
3 0

speed of sound wave depends on elasticity of medium and density of medium

it is given by formula

v = \sqrt{\frac{E}{/rho}}

now if wave travel through solid then its speed is maximum while if it travel from gas then its speed is minimum

so initially its speed is given as 4000 m/s and suddenly decrease to 1500 m/s

so here we can say that its medium will change from solid to liquid

<em>so sound will encounter with water </em>

You might be interested in
You have a chemical sealed in a glass container filled with air. The glass container has a mass of 200.0 grams and the chemical
just olya [345]

Answer:

the total mass after chemical burn is 700 gram

Explanation:

Given data

glass mas s= 200 gram

chemical mass = 500 gram

total mass = 700 gram

to find out

what is the total mass after chemical burn

solution

we have given 200 gram + 500 gram = 700 gram

and we know here according to question that

container is sealed so total mass remain in container before burning and after burning

no air will release in seal container so

mass will be same as 700 gram

hence the total mass after chemical burn is 700 gram

3 0
4 years ago
A wave pulse travels along a string at a speed of 200 cm/s. What will be the speed if:
34kurt

Answer:

a) v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s

The velocity increase by a factor of \sqrt{2}

b) v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s

The velocity decrease by a factor of 2.

c) v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s

The velocity increase by a factor of 2

d) v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s

The velocity not changes.

Explanation:

For this case we know that the velocity is v = 200 cm/s = 2m/s

v_f represent the final velocity after the changes specified,

Part a

The formula for the speed of a wave in a string is given by:

v = \sqrt{\frac{T}{\rho}}

And the linear density is defined as:

\rho = \frac{m}{L}

And if we replace this we got:

v = \sqrt{\frac{TL}{m}}

If the tension mass is doubled we have this:

v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s

The velocity increase by a factor of \sqrt{2}

Part b

If we mass is quadrupled we have this:

v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s

The velocity decrease by a factor of 2.

Part c

If the length is quadrupled we have this:

v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s

The velocity increase by a factor of 2

Part d

For this case we know that the mass and the length are both quadrupled and we got:

v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s

The velocity not changes.

7 0
3 years ago
the volume of ice block is 2400cm^3 and its density is 0.9 g/cm^3. how much part of it remains above the surface of water when i
stiks02 [169]

Answer:

240 cm³

Explanation:

Weight = Buoyancy

mg = ρVg

m = ρV

(0.9 g/cm³ × 2400 cm³) = (1 g/cm³) V

V = 2160 cm³

The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.

4 0
3 years ago
At what water temperature will additional heat energy need to be added before the temperature will change again?
Katyanochek1 [597]
That would be 0 degrees Celsius aka the melting point of water.... If you look at the diagram I attached you notice that at 0 degrees Celsius it is flat, this is because much heat is needed at this point for water to rise to 1 degree... It is the same for the boiling point (100)

Hope this helps! (If correct, please rank as brainliest answer) :)
7 0
3 years ago
2.
skelet666 [1.2K]
Answer: 290 W
Explanation: I hope this helps you
6 0
3 years ago
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