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joja [24]
3 years ago
7

You are attending the State Fair, and at the midway games, you come across the one rare, crooked carnival game. In this game, ba

lls have to be launched into holes in the wall. Placing the ball in the topmost hole wins you a giant cuddly bear, so you decide to aim for it. The wall is placed 2 m away from the launcher, and the top hole is 1.5 m above the launcher. The holes are designed in such a way that the ball will only go through if it is travelling horizontally when it reaches the hole. You can adjust the launch speed and angle of the ball. What settings for the speed and angle (measured from the horizontal) should you set the launcher in order to win the cuddly bear.
Physics
1 answer:
Anettt [7]3 years ago
4 0

Answer:

Explanation:

At the top , horizontal displacement = 2 m .

vertical displacement = 1.5 m .

Let time to reach the hole be t . Let the ball is launched at angle θ with horizontal with velocity u .

ucosθ x t = 2

from v = u - 2gt

0 = usinθ - 2gt

usinθ =  2gt

v² = u² - 2gh

u²sin²θ = 2 g h

u²sin²θ = 2 x 9.8 x 1.5

usinθ =  5.42

usinθ =  2gt

2gt = 5.42

t = .2765 s

ucosθ x t = 2

ucosθ x .2765 = 2

ucosθ = 7.23

usinθ =  5.42

dividing ,

Tanθ = .75

θ = 37°

usin37 =  5.42

u = 9.03 m /s

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Otion
Scorpion4ik [409]

Answer:

SKID

Explanation:

In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.

Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.

Y axis y

     N- W = 0

     N = W

X axis (radial)

        fr = m a

the acceleration in the curve is centripetal

         a = \frac{v^2}{r}

the friction force has the expression

        fr = μ N

we substitute

       μ mg = m v²/r

       v = \sqrt{\mu g r}

we calculate

      v = \sqrt{0.1 \ 9.8 \ 3}

      v = 1,715 m / s

to compare with the cyclist's speed let's reduce to the SI system

        v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s

We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID

5 0
3 years ago
What would be the first thing you would do if your clothes caught fire while working in a laboratory? select one of the options
Ksivusya [100]
<span>c. run towards a source of water to extinguish the fire </span>
3 0
3 years ago
Each ball has a negligible size and a mass of 11.5 kg and is attached to the end of a rod whose mass may be neglected. The rod i
Digiron [165]

Answer:

3.31m/s

Explanation:

Angular momentum for 3s is

L = L_i_n_i + L_3_s

L = 2(11.5kg) + \int\limits^ {3s}_ {0s} {(t^2 + 2)} \, dt

L = 23kg+(\frac{t^3}{3} +2t)^ {3s}_ {0s}\\\\L=38kgm/s

Moment if inertia is

I = 2ml^2

I = 2(11.5)(0.5)^2\\\\I=5.75kgm^2

Angular speed

ω = L/I

= 38 / 5.75\\\\=6.61

The speed of each ball is

V = ωL

= 6.61\times0.5\\\\= 3.31m/s

7 0
3 years ago
In which of these examples is the greatest movement occurring?
Elenna [48]

Answer:

not clear pic...but it's definitely not A)

7 0
3 years ago
The massless spring of a spring gun has a force constant k=12~\text{N/cm}k=12 N/cm. When the gun is aimed vertically, a 15-g pro
ASHA 777 [7]

Answer:

0.011 m.

Explanation:

Energy stored in the spring = Energy of the projectile.

1/2ke² = mgh ................ Equation 1

Where k = spring constant, e = extension or compression, m = mass of the projectile, g = acceleration due to gravity, h = height.

make e the subject of the equation

e = √(2mgh/k)............................. Equation 2

Given: k = 12 N/cm = 1200 N/m, m = 15 g = 0.015 kg, h = 5.0 m

Constant: g = 9.8 m/s²

Substitute into equation 2

e = √(2×0.015×5/1200)

e = √(0.15/1200)

e = √(0.000125)

e = 0.011 m.

4 0
3 years ago
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