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joja [24]
4 years ago
7

You are attending the State Fair, and at the midway games, you come across the one rare, crooked carnival game. In this game, ba

lls have to be launched into holes in the wall. Placing the ball in the topmost hole wins you a giant cuddly bear, so you decide to aim for it. The wall is placed 2 m away from the launcher, and the top hole is 1.5 m above the launcher. The holes are designed in such a way that the ball will only go through if it is travelling horizontally when it reaches the hole. You can adjust the launch speed and angle of the ball. What settings for the speed and angle (measured from the horizontal) should you set the launcher in order to win the cuddly bear.
Physics
1 answer:
Anettt [7]4 years ago
4 0

Answer:

Explanation:

At the top , horizontal displacement = 2 m .

vertical displacement = 1.5 m .

Let time to reach the hole be t . Let the ball is launched at angle θ with horizontal with velocity u .

ucosθ x t = 2

from v = u - 2gt

0 = usinθ - 2gt

usinθ =  2gt

v² = u² - 2gh

u²sin²θ = 2 g h

u²sin²θ = 2 x 9.8 x 1.5

usinθ =  5.42

usinθ =  2gt

2gt = 5.42

t = .2765 s

ucosθ x t = 2

ucosθ x .2765 = 2

ucosθ = 7.23

usinθ =  5.42

dividing ,

Tanθ = .75

θ = 37°

usin37 =  5.42

u = 9.03 m /s

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A pump lifts 400 kg of water per hour a height of 4.5 m .
nasty-shy [4]

Answer:

Power = Work / Time

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Also, 4.9 Watts / (746 Watts / Horsepower) = .0066 Hp

6 0
3 years ago
A clock radio is rated as 30 w of power output. if the radio also draws 30 w at 120 v, which will the current draw be?
g100num [7]
P = IV

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Current = 0.25A  
4 0
3 years ago
The density of gold is 19.3. G/cm(3). If a nugget of iron pyrite and nugget of gold each have a mass of 50 g, what can you concl
tangare [24]
The pyrite will be bigger, because its density is much lower.

I <em>do</em> know that the gold's volume will be 2.5906 (With a bunch more numbers after it)

50 divided by 19.3 = 2.5906
5 0
3 years ago
The stopwatch used by a student to measure velocity of a pulse in a slinky was of least count 0.1 second. He stops the stopwatch
sweet-ann [11.9K]

Least count of the pulse stopwatch is given by

\Delta t = 0.1 s

this means each division of the stopwatch will measure 0.1 s of time

After 3 journeys from one end to other we can see that total time that is measured here is shown by the clock as 52nd division

So here total time is given as

Time = (Number of division) (Least count)

now we will have

T = 52 \times 0.1s

T = 5.2 s

4 0
3 years ago
A car is running at the speed of 45km/hr see a child 25 meter ahead and suddenly apllies a brakes. If the retradation of the car
kenny6666 [7]

Answer:

The car stops in 7.78s and does not spare the child.

Explanation:

In order to know if the car stops before the distance to the child, you take into account the following equation:

x=x_o+v_ot-\frac{1}{2}at^2        (1)

vo: initial speed of the car = 45km/h

a: deceleration of the car = 2 m/s^2

t: time

xo: initial distance to the child = 25m

x: final distance to the child = 0m

It is necessary that the solution of the equation (1) for time t are real.

You first convert the initial speed to m/s, then replace the values of the parameters and solve the quadratic polynomial for t:

45\frac{km}{h}*\frac{1h}{3600s}*\frac{1000m}{1km}=12.5\frac{m}{s}

0=25+12.5t-2t^2\\\\2t^2-12.5t-25=0\\\\t_{1,2}=\frac{-(-12.5)\pm \sqrt{(-12.5)^2-4(2)(-25)}}{2(2)}\\\\t_{1,2}=\frac{12.25\pm 18.87}{4}\\\\t_1=7.78s\\\\t_2=-1.65s

You take the first value t1 because it has physical meaning.

The solution for t is real, then, the car stops in 7.78s and does not spare the child.

4 0
3 years ago
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