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Zepler [3.9K]
3 years ago
5

The high specific heat and cohesive forces characteristic of water are a result of Group of answer choices Hydrogen bonding betw

een water molecules Covalent bonds between the O and two H's of water molecules Ionic bonds between the H and OH Dissociation of H2O into H and OH-O
Physics
1 answer:
Jobisdone [24]3 years ago
3 0

Answer:

A. Hydrogen bonding between water molecules.

Explanation:

Specific heat capacity of water can be defined as the amount of heat a gram of water must lose or absorb in order to change its temperature by a degree Celsius. It is measured in Joules per kilogram per degree Celsius (J/kg°C). Generally, the specific heat capacity of water is 4.182J/kg°C and is the highest among liquids.

Cohesion is a property of water and typically refers to the attraction between molecules of water which holds them together.

The high specific heat and cohesive forces characteristic of water are a result of hydrogen bonding between water molecules. A hydrogen bond is formed in water due to its polarity (opposite charges between water molecules), which causes each water molecule to attract other water molecules. An atom of hydrogen of each water molecule bonds with the electron lone pair on atom of oxygen of a close water molecule.

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Which is the biggest terrestrial planet? <br> A. Mercury <br> B. Venus <br> C. Earth <br> D. Mars
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Answer:

C. Earth give me brainlest its correct! Hope this helps!

Explanation:

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A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with
gulaghasi [49]

Answer:

8.8 cm

31.422 cm/s

Explanation:

m = Mass of block = 0.6 kg

k = Spring constant = 15 N/m

x = Compression of spring

v = Velocity of block

A = Amplitude

As the energy of the system is conserved we have

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{0.6\times 0.44^2}{15}}\\\Rightarrow A=0.088\ m\\\Rightarrow A=8.8\ cm

Amplitude of the oscillations is 8.8 cm

At x = 0.7 A

Again, as the energy of the system is conserved we have

\dfrac{1}{2}kA^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2\\\Rightarrow v=\sqrt{\dfrac{k(A^2-x^2)}{m}}\\\Rightarrow v=\sqrt{\dfrac{15(0.088^2-(0.7\times 0.088)^2)}{0.6}}\\\Rightarrow v=0.31422\ m/s

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4 0
3 years ago
Which statement is true about an object moving in a circular motion due to centripetal force, F, when the mass is doubled? A. It
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Force = [Mass x (velocity)^2]/Radius
Therefore,
The mass and the force are directly proportional.If you double the mass,the force will be doubled too.

A. Its centripetal force would <span>be doubled.</span>
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3 years ago
A ball tossed vertically upward from the ground next to a building passes the bottom of a window 1.8 s after being tossed and pa
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The ball takes 0.2 sec to travel the height of the window, which is 2 m.

 Then the speed of the ball at that time was

v = \frac{d}{t}

v = \frac{2}{0.20}

v = 10\ \frac{m}{s}

We know that:

v = v_0 -gt

Where v_0 is the initial velocity.

So:

10 = v_0 -9.8(2)

10 + 9.8(2) = v_0

v_0 = 29.6\ m / s

Then we have the equation for the position as a function of time.

r = r_0 + v_0t - \frac{1}{2}gt^2

Where

r_0 = initial position

r = position as a function of time

v_0 = initial velocity

g = acceleration of gravity

t = time.

If the ball is thrown from the ground then:

r_0 = 0 m

We want to find now the distance between the window and the ground.

When the ball reaches the bottom of the window t = 1.8s

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r = 0 + 29.6(1.8) - 0.5(9.8)(1.8)^2

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Finally, to know how high the ball rises we must know at what moment the vertical velocity of the ball is zero.

v = v_0 -gt\\\\0 = v_0 -gt\\\\gt = v_0\\\\t = \frac{29.6}{9.8}

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Now we replace t in the position equation

r = 0 + 29.6(3.02) -0.5(9.8)(3.02)^2

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mariarad [96]

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So, the ratio of masses X/Y is 0.0847

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