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vazorg [7]
3 years ago
6

Which statement is true about an object moving in a circular motion due to centripetal force, F, when the mass is doubled? A. It

s centripetal force would be doubled. B. Its centripetal force would be unaltered. C. Its centripetal force would be reduced by half. D. Its centripetal force would be reduced by a factor of 1/4.
Physics
1 answer:
Allushta [10]3 years ago
3 0
Force = [Mass x (velocity)^2]/Radius
Therefore,
The mass and the force are directly proportional.If you double the mass,the force will be doubled too.

A. Its centripetal force would <span>be doubled.</span>
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A radar used to detect the presence of aircraft receives a pulse that has reflected off an object 5 ✕ 10−5 s after it was transm
Sunny_sXe [5.5K]

Answer:

7500 m

Explanation:

The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.

We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so

d = 2L

In a time of

t=5\cdot 10^{-5}s

Electromagnetic waves travel in a vacuum at the speed of light, which is equal to

c=3.0\cdot 10^8 m/s

Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:

d=vt (1)

where

v=c=3.0\cdot 10^8 m/s

t=5\cdot 10^{-5}s

d=2L, where L is the distance between the radar and the object

Re-arranging eq(1) and substituting, we find L:

L=\frac{vt}{2}=\frac{(3.0\cdot 10^8)(5\cdot 10^{-5})}{2}=7500 m

7 0
4 years ago
A car is left overnight in a parking lot. What is its instantaneous speed at 12:01 a.m.?​
STatiana [176]

Answer:

0 mph

Explanation:

4 0
3 years ago
Read 2 more answers
A point charge gives rise to an electric field with magnitude 2 N/C at a distance of 4 m. If the distance is increased to 20 m,
worty [1.4K]

Answer:

0.08 N/C

Explanation:

Electric Field: This is defined as the force per unit charge exerted at a point. The expression for electric field is given as,

E = Kq/r².............................. Equation 1

Where E = Electric Field, q = Charge, k = proportionality constant, r = distance.

making q the subject of the equation,

q = Er²/k............................... Equation 2

Given: E = 2 N/C, r = 4 m,

Substitute into equation 2

q = 2(4)²/k

q = 32/k C.

When r is increased to 20 m,

E = k(32/k)/20²

E = 32/400

E = 0.08 N/C.

Hence the electric Field = 0.08 N/C

5 0
4 years ago
In a downhill ski race, surprisingly, little advantage is gained by getting a running start. (This is because the initial kineti
Sergio [31]

Answer:

Part a)

v_f = 25.2 m/s

t = 5.48 s

Part b)

v_f = 25.32 m/s

t = 4.96 s

Explanation:

Part a)

When ski start from rest

v_f^2 - v_i^2 = 2 a d

on this inclined plane we know that the acceleration is given as

a = g sin\theta

a = 9.81 sin28

a = 4.6 m/s^2

now for final speed

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2(4.6)(69)

v_f = 25.2 m/s

now time taken by the ski to reach the bottom is given as

v_f = v_i + at

25.2 = 0 + 4.6 t

t = 5.48 s

Part b)

Now when ski start with initial speed of 2.5 m/s

then we will have

v_f^2 - v_i^2 = 2 a d

v_f^2 - 2.5^2 = 2(4.6)(69)

v_f = 25.32 m/s

now time taken by the ski to reach the bottom is given as

v_f = v_i + at

25.32 = 2.5 + 4.6 t

t = 4.96 s

3 0
3 years ago
A toy boat moves horizontally in a pond. The horizontal position of the boat in meters over time is shown below. What is the dis
arsen [322]

Answer:

displacement=-21

distance=39

Explanation:

5 0
3 years ago
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