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patriot [66]
3 years ago
14

When the number of electrons striking the anode of an x-ray tube is increased, the ____ of the emitted X-Ray increases.

Physics
1 answer:
Sphinxa [80]3 years ago
4 0
When the number of electrons striking the anode of an X-ray tube is increased, the density of the emitted x-ray increases
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A car travels on a straight, level road. (a) Starting from rest, the car is going 38 ft/s (26 mi/h) at the end of 4.0 s. What is
lbvjy [14]

Answer:

a)9.5\frac{ft}{s^2}\\ b) 12.66\frac{ft}{s^2}

Explanation:

A body has acceleration when there is a change in the velocity vector, either in magnitude or direction. In this case we only have a change in magnitude. The average acceleration represents the speed variation that takes place in a given time interval.

a)

a_{avg}=\frac{\Delta v}{\Delta t}\\a_{avg}=\frac{v_{f}-v_{i}}{t_{f}- t_{i}}\\a_{avg}=\frac{38\frac{ft}{s}-0}{4 s- 0}=9.5\frac{ft}{s^2}\\

b)

a_{avg}=\frac{\Delta v}{\Delta t}\\a_{avg}=\frac{v_{f}-v_{i}}{t_{f}- t_{i}}\\a_{avg}=\frac{76\frac{ft}{s}-38\frac{ft}{s}}{7 s- 4s}\\a_{avg}=\frac{38\frac{ft}{s}}{3s}=12.66\frac{ft}{s^2}

8 0
3 years ago
In which of the following situations would convection currents most likely occur?
poizon [28]

Answer: Option (B) is the correct answer.

Explanation:

Convection is defined as a process in which a fluid (liquid or gas) is heated and the cooler liquid (more dense) settles or sinks at the bottom whereas a hotter material (less dense) will rises to the top.

For example, ice being less dense (cooler material) will float in a lake whereas liquid water being more dense will sink at the bottom.

Thus, we can conclude that situation in which convection currents most likely occur is within the water in a lake as ice forms on the top.

4 0
3 years ago
Read 2 more answers
A 1.50-m string of weight 0.0125 N is tied to the ceil- ing at its upper end, and the lower end supports a weight W. Ignore the
Elena L [17]

The wave equation is missing and it is y(x,t) = (8.50 mm)cos(172 rad/m x − 4830 rad/s t)

Answer:

A) 0.0534 seconds

B) 0.67N

C) 41

D) (8.50 mm)cos(172 rad/m x + 4830 rad/s t)

Explanation:

we are given weight of string = 0.0125N

Thus, since weight = mg

Then, mass of string = 0.0125/9.8

Mass of string = 1.275 x 10⁻³ kg

Length of string; L= 1.5 m .

mass per unit length; μ = (1.275 x 10⁻³)/1.5

μ = 0.85 x 10⁻³ kg/m

We are given the wave equation: y(x,t) = (8.50 mm)cos(172 rad/m x − 4830 rad/s t)

Now if we compare it to the general equation of motion of standing wave on a string which is:

y(x,t) = Acos(Kx − ω t)

We can deduce that

angular velocity;ω = 4830 rad/s

Wave number;k = 172 rad/m

A) Velocity is given by the formula;

V = ω/k

Thus, V = 4830/172 m/s

V = 28.08 m /s

Thus time taken to go up the string = 1.5/28.08 = 0.0534 seconds

B) We know that in strings,

V² = F/μ

Where μ is mass per unit length and V is velocity.

Thus, F = V²*μ =28.08² x 0.85 x 10⁻³

F = 0.67N

C) Formula for wave length is given as; wave length;λ = 2π /k

λ = 2 x π/ 172

λ = 0.0365 m

Thus, number of wave lengths over whole length of string

= 1.5/0.0365 = 41

D) The equation for waves traveling down the string

= (8.50 mm)cos(172 rad/m x + 4830 rad/s t)

8 0
3 years ago
Calculate the velocity of a car that travelled 120km in 2 hours<br>​
Naddik [55]
I need context poggg
5 0
2 years ago
A 50.0 kg rock starting from rest free falls through a distance of 300.0 m with no air resistance. Find the momentum change of t
Kobotan [32]

Answer:

Momentum change of the rock = 3835 kgm/s

Chane in earth's velocity = 6.4 x 10⁻²² m/s

Explanation:

m = 50.0 kg, M = 6.0 x 10²⁴ kg

d = 300.0 m

final velocity of rock = v, v² = 2gd = 2 * 9.81 * 300, so v = 76.7 m/s

Momentum change of the rock = mv = 50.0 * 76.7 = 3835 kgm/s

Inital momentum of the rock+earth system = 0

final momentum = 0 (momentum conservation)

momentum of rock and momentum of earth are same magnitude and opposite directions.

mv - MV = 0

Chane in earth's velocity = mv/M = 3835/(6.0 x 10²⁴) = 6.4 x 10⁻²² m/s

5 0
2 years ago
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