Answer:
d) 289.31 m
Explanation:
Energy provided by potential energy = mgh = m x 9.8x 200 sin10.5 = 357.18m
Energy used by friction = μmgcos 10.5 x 200 = .075 x m x 9.8 x cos 10.5 x200 = 144.54 m .
Energy used by friction on plain surface = μmg x d.( dis distance covered on plain ) =.075x m x 9.8 xd = .735 m d
To equate
357.18 m -144.54 m = .735 m d
d = 289.31 m .
Answer:
1.03 m/s
Explanation:
I'm too lazy to write the explanation down but my teacher graded this and it was right
<em>Since the wagon is being pulled down hill with a constant velocity, all the forces of the wagon would be (C) increasing.</em>
<em>You are correct! **</em>
Answer: a) 5 x 10^5 kg/s b) 444 MW
Explanation:
Kinetic energy per unit mass Ke is
Ke = V^2 / 2
Ke = 3^2 / 2 = 4.5 J/kg = 0.0045 kJ/kg
Now potential energy per unit mass Pe is
Pe = g x z = 9.8 x 90 = 882.9 J/kg = 0.8829 kJ/kg
The total mechanical energy of the River per unit mass e = Ke + Pe = 0.0045 + 0.8829 = 0.88744 J/kg
M = P x V = 1000 x 500 = 5 x 10^5 kg/s
b) power generation potential of the entire river at the location Wmax = Emech = M x Emech = 500,000 x 0.88744 = 444,000kW = 444MW