Answer:
19.33°C
Explanation:
To find the value of T you use the following formula:
v: speed of sound
To calculate v you use:
λ: wavelength = 0.651m
f: = 545Hz
by replacing :
Finally, by replacing in the first formula you obtain:
T = 19.33°C
Fill in the blank. Consider the inverse square law: When light leaves a light bulb, it spreads out over more and more space as i
1 answer:
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Answer:
θ = 30°
Explanation:
Firts, the angle when the beam of light passes through the block cam be calculated using Snell Law:
<u>Where</u>:
n₁: is the index of refraction of the incident medium (air) = 1
θ₁: is the incident angle = 30°
n₂: is the medium 2 (plastic) = 1.46
θ₂: is the transmission angle
Hence, θ₂ is:
Now, when the beam of light re-emerges from the opposite side, we have:
n₁: is the index of refraction of the incident medium (plastic) = 1.46
θ₁: is the incident angle = 20.03°
n₂: is the medium 2 (air) = 1
θ₂: is the transmission angle
Hence, the angle to the normal to that surface (θ₂) is:
Therefore, we have that the beam of light will come out at the same angle of when it went in, since, it goes from air and enters to a plastic medium and then enters again in this medium to go out to air again. This was proved using the Snell Law.
I hope it helps you!
Correct question:
Consider the motion of a 4.00-kg particle that moves with potential energy given by
a) Suppose the particle is moving with a speed of 3.00 m/s when it is located at x = 1.00 m. What is the speed of the object when it is located at x = 5.00 m?
b) What is the magnitude of the force on the 4.00-kg particle when it is located at x = 5.00 m?
Answer:
a) 3.33 m/s
b) 0.016 N
Explanation:
a) given:
V = 3.00 m/s
x1 = 1.00 m
x = 5.00
At x = 1.00 m
= 4J
Kinetic energy = (1/2)mv²
= 18J
Total energy will be =
4J + 18J = 22J
At x = 5
= -0.24J
Kinetic energy =
= 2Vf²
Total energy =
2Vf² - 0.024
Using conservation of energy,
Initial total energy = final total energy
22 = 2Vf² - 0.24
Vf² = (22+0.24) / 2
= 3.33 m/s
b) magnitude of force when x = 5.0m
At x = 5.0 m
= 0.016N