What is part of meiosis but not of mitosis
2 answers:
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Answer:
0.1795 M
Explanation:
From the given information:
The equation is:
From the above equation, the reaction will go to completion due to the strong base:
At the equivalence point, moles of acid (HF) will be equal to moles of base (KOH)
Thus. since moles of HF = moles of KOH
Then; 0.020 × 0.393 M = 0.02379 × (x) M
(x) M =
(x) = 0.3304 M
Thus, the molarity of KOH = 0.3304 M
Using the balanced neutralization reaction;
moles of HF = moles of KOH = moles of conjugate base = 0.00786 mol
∴
Volume = 0.020 L + 0.02379 L
Volume = 0.04379 L
Volume of the solution = 0.04379 L
Therefore; Molarity =
Molarity =
Molarity = 0.17949 mol/L
= 0.1795 M
Answer : The amount of heat absorbed are, 258485.5 J
Solution :
Formula used :
where,
Q = heat gained = ?
m = mass of water = 650 g
c = specific heat of water =
= final temperature =
= initial temperature =
Now put all the given values in the above formula, we get the final temperature of copper.
Therefore, the amount of heat absorbed are, 258485.5 J