Complete Question
A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane
The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?
Answer:
The mass of caffeine extracted is
Explanation:
From the question above we are told that
The K value is
The mass of the caffeine is
The volume of water is
The volume of caffeine is
The number of times the extraction was done is n = 3
Generally the mass of caffeine that will be extracted is
substituting values
V = nRT/P
V = 0.685 mol*(.0821 L*atm/K*mol)*273 K/1 atm
The correct answer is c. Temperature is the average kinetic energy of a sample so if two samples have the same temperature they will also have the same average kinetic energy. I hope this helps. Let me know if anything is unclear.
Neon is usually found in the form of a gas with molecules consisting of a single Neon atom. Neon is a rare gas that is found in the Earth's<span> atmosphere at 1 part in 65,000. I'm not 100% sure but i am pretty sure it is found in both places but more is in South America. Just incase, wait for someone else to answer.</span>
mass = 12.2 kg
Explanation:
To find the mass we use the following formula (Newton's Second Law of Motion):
force = mass × acceleration
mass = force / acceleration
mass = 2.32 N / 0.19 m/s²
mass = 12.2 kg
Learn more about:
Newton's Second Law of Motion
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