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motikmotik
3 years ago
8

In the reaction:

Chemistry
1 answer:
Ghella [55]3 years ago
5 0

Answer:

The answer is D because NH4+and OH- it will be

N-1. N-1,

H-5

O-1 H-5

O-1

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An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to -5°C. Assume that there is no volume change in t
dmitriy555 [2]

Answer:

P₂ = 2.7 atm

Explanation:

Given data:

Initial temperature = 30°C

Initial pressure = 3.00 atm

Final temperature = -5°C

Final pressure = ?

Solution:

Initial temperature = 30°C = 30 + 273 = 303 K

Final temperature = -5°C = -5 + 273 = 268 K

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

3.0 atm / 303 K = P₂/268 K

P₂ = 3.0 atm × 268 K / 303 K

P₂ = 804 atm. K /293 K

P₂ = 2.7 atm

7 0
3 years ago
Can someone help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Thank you.
8090 [49]
7.62 decameters, 7620 centimeters
7 0
3 years ago
Read 2 more answers
What is the name of this hydrocarbon
KengaRu [80]
Depending on the strictness of your teacher you can name it as either of the following:
2-methyl-propane or iso-propane
3 0
3 years ago
Read 2 more answers
What is the pH of a solution if the [H⁺] = 4.2 x 10⁻¹¹ M
liraira [26]

Answer:

10.4

Explanation:

-log(4.2x10^-11) = 10.37 = 10.4

3 0
2 years ago
Determine the expression for the equilibrium constant, KcKcK_c, for the reaction by identifying which terms will be in the numer
Yakvenalex [24]

Answer: Hello your question lacks some details below is the complete question

answer :

Numerator = CH₃OH

Denominator = (CO ) ( H₂)²

Explanation:

CO + 2H₂ ⇄ CH₃OH  ( formation of methanol )

hence for the equilibrium constant Kc

Numerator = CH₃OH

Denominator = (CO ) ( H₂)²

<u><em>Placing into the Bin </em></u>

Numerator : CH₃OH

Denominator : (CO ) ( H₂)²

Not Used : ( CO )² ,  H₂ ,  ( CH₃OH ) ²

8 0
3 years ago
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