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motikmotik
3 years ago
8

In the reaction:

Chemistry
1 answer:
Ghella [55]3 years ago
5 0

Answer:

The answer is D because NH4+and OH- it will be

N-1. N-1,

H-5

O-1 H-5

O-1

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Lance is a 60-kg runner who, on a good day, runs at a speed of 5 m/s. What is his kinetic energy when he runs at this speed? *
Contact [7]

Answer:

His kinetic energy when he runs at that 5 m/s is 750 joules

Explanation:

The given information are;

The mass of, Lance, the runner = 60-kg

The speed by which Lance is running = 5 m/s

The kinetic energy, KE, is given by the relation;

KE = 1/2×m×v²

Where;

m = The mass = 60-kg

v = The instantaneous speed of motion = 5 m/s

The kinetic energy can be found by substituting the values of the variables in the kinetic energy equation as follows;

KE = 1/2 × 60 kg × (5 m/s)² = 750 joules

His kinetic energy when he runs at that 5 m/s is 750 joules.

7 0
3 years ago
Which of the following does not release carbon back into the atmosphere?
Aliun [14]
Respiration and or photosynthesis
8 0
3 years ago
How do water molecules dissolve a salt?
Artist 52 [7]

Answer:

Water can dissolve salt because the positive part of water molecules attracts the negative chloride ions and the negative part of water molecules attracts the positive sodium ions. The amount of a substance that can dissolve in a liquid (at a particular temperature) is called the solubility of the substance.

Explanation:

5 0
3 years ago
2. A sample of a gas is occupying a 1500 mL container at a pressure of 3.4 atm and a temperature of 25
lora16 [44]

2. The new pressure, given the data is 3.0 atm

3. The new temperature in K is 361 K

4. The new temperature in K is 348 K

<h3>2. How to determine the new pressure</h3>
  • Initial volume (V₁) = 1500 mL
  • Initial pressure (P₁) = 3.4 atm
  • Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
  • New temperature (T₂) = 75 °C = 75 + 273 = 348 K
  • New Volume (V₂) = 2000 mL
  • New pressure (P₂) = ?

The new pressure of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(3.4 × 1500) / 298 = (P₂ × 2000) / 348

Cross multiply

P₂ × 2000 × 298 = 3.4 × 1500 × 348

Divide both sides by 2000 × 298

P₂ = (3.4 × 1500 × 348) / (2000 × 298)

P₂ = 3.0 atm

<h3>3. How to determine the new temperature</h3>
  • Initial volume (V₁) = 450 mL
  • Initial pressure (P₁) = 167 KPa
  • Initial temperature (T₁) = 295 K
  • New pressure (P₂) = 230 KPa
  • New Volume (V₂) = 400 mL
  • New temperature (T₂) =?

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(167 × 450) / 295 = (230 × 400) / T₂

Cross multiply

T₂ × 167 × 450 = 295 × 230 × 400

Divide both sides by 167 × 450

T₂ = (295 × 230 × 400) / (167 × 450)

T₂ = 361 K

<h3>4. How to determine the new temperature</h3>
  • Initial volume (V₁) = 3.6 L
  • Initial pressure (P₁) = 9.2 atm
  • Initial temperature (T₁) = 298 K
  • New Volume (V₂) = 5.3 L
  • New pressure (P₂) = 7.3 atm
  • New temperature (T₂) =?

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(9.2 × 3.6) / 298 = (7.3 × 5.3) / T₂

Cross multiply

T₂ × 9.2 × 3.6 = 298 × 7.3 × 5.3

Divide both sides by 9.2 × 3.6

T₂ = (298 × 7.3 × 5.3) / (9.2 × 3.6)

T₂ = 348 K

Learn more about gas laws:

brainly.com/question/6844441

#SPJ1

7 0
2 years ago
How do you find the average rate for a reaction *FOR TEST REVISION* urgent ❤️❤️ pls be quick
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We are given the concentration of A at 20s(0 .54m) and at 40s (0.30m) and asked the average rate of reaction over this time interval. Plan the average rate is given by the change in concentration divided by the change in time
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