Answer:
the electric field is 42.8×10^6 N/C
Explanation:
let k be the coulomb constant, Q be the charge distribution , R be the radius of the disk and x be the distance from the center.
k = 8.98755×10^9 N×m^2/c^2
Q = 6.1×10^-6 C
R = 4.9×10^-2 m
x = 3.1×10^-3 m
Answer:
Explanation:
Total length of the wire is 29 m.
Let the length of one piece is d and of another piece is 29 - d.
Let d is used to make a square.
And 29 - d is used to make an equilateral triangle.
(a)
Area of square = d²
Area of equilateral triangle = √3(29 - d)²/4
Total area,
Differentiate both sides with respect to d.
For maxima and minima, dA/dt = 0
d = 8.76 m
Differentiate again we get the
(a) So, the area is maximum when the side of square is 29 m
(b) so, the area is minimum when the side of square is 8.76 m