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3 years ago

10

How many significant figures does 0.00340 have?

2 answers:

Delicious77 [7]3 years ago

8 0

3 because the 0 is behind the decimal and 34 and the other zeros arent behind a non zero digit and 3 and 4 are non zero digits

True [87]3 years ago

4 0

Greetings!

"<span>How many significant figures does 0.00340 have?"...

A significant figure is:
-A non zero number
-A zero in between non zero numbers
-Trailing zeros to the right of the decimal point

Therefore, this number has three significant figures:
3,4,0

Hope this helps.
-Benjamin</span>

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What is moral duty?Please tell me the answer of this question.

egoroff_w [7]

Explanation:

Moral duties are the duties performed by the people on the basis of humanity and moral values. The following are some of the moral duties :

Respecting elders and loving juniors
Helped the needy , poor and helpless people
Having friendly behavior with others
Respecting everyone as human being
Being obedient and respectful to parents , elderly people and teachers.
Living ideal and respectful life

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3 years ago

A pencil rolls horizontally of a 1 meter high desk and lands .25 meters from the base of the desk. How fast was the pencil rolli

vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

$x=V_{o} cos\theta t$ (1)

$y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2}$ (2)

Where:

$x=0.25 m$ is the horizontal displacement of the pencil

$V_{o}$ is the pencil's initial velocity

$\theta=0\°$ since we are told the pencil rolls <u>horizontally</u> before falling

$t$ is the time since the pencil falls until it hits the ground

$y_{o}=1 m$ is the initial height of the pencil

$y=0$ is the final height of the pencil (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity, always acting vertically downwards

Begining with (1):

$x=V_{o} cos(0\°) t$ (3)

$x=V_{o}t$ (4)

Finding $t$ from (2):

$0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2}$ (5)

$t=\sqrt{\frac{-2y_{o}}{g}}$ (6)

Substituting (6) in (4):

$x=V_{o}\sqrt{\frac{-2y_{o}}{g}}$ (7)

Isolating $V_{o}$ :

$V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}}$ (8)

$V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}}$ (9)

Finally:

$V_{o}=0.55 m/s$

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3 years ago

Please help ASAP WILL GIVE BRAINLIEST

Westkost [7]

Answer:

D

Explanation: It makes the most sense. Plz mark brainliest

5 0

3 years ago

Read 2 more answers

What is the potential energy of a 5kg rock that is 7m high on a hill

Goryan [66]

Explanation:

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3 years ago

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daser333 [38]

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3 years ago