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3 years ago

Is it possible to draw three lines in two planes such that all three lines are skew?

Mathematics

2 answers:

nata0808 [166]3 years ago

8 0

Yes; it is possible

<span>If the planes are parallel to each other then they don't intersect. </span>

<span>There can also be two or more lines on different planes which do not intersect each other. These lines are called skew lines.</span>

dalvyx [7]3 years ago

8 0

Answer with explanation:

→Two lines in three dimensional plane are said to be Skew if they are neither parallel nor Intersecting.

→Skew lines can be drawn in three dimensional plane only.

→Drawn two skew lines in a Plane , and then drawn another line in a plane and found that , they are skew.

⇒Yes, it is possible to draw three lines in two planes such that all three lines are skew.

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2 years ago

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ankoles [38]

Answer:

41.29 cm²

Step-by-step explanation:

From the question,

Area of the shaded portion = Area of the circle - area of the square.

A' = πr²-L²...… Equation 1

Where A' = Area of the shade portion, r = radius of the circle, L = length of the square, π = pie

Given: r = 4 cm, L = 3 cm

Constant: π = 22/7.

Substitute these values into equation 1

A' = [(22/7)×4²]-3²

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A' = 41.29 cm²

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2 years ago

A rectangle with a length of L and a width of W has a diagonal of 10 inches. Express the perimeter P of the rectangle as a funct

KatRina [158]

<h2>Answer:</h2>

The expression which represents the perimeter P of the rectangle as a function of L is:

$Perimeter=2(L+\sqrt{100-L^2})$

<h2>Step-by-step explanation:</h2>

The length and width of a rectangle are denoted by L and W respectively.

Also the diagonal of a rectangle is: 10 inches.

We know that the diagonal of a rectangle in terms of L and W are given by:

$10=\sqrt{L^2+W^2}$

( Since, the diagonal of a rectangle act as a hypotenuse of the right angled triangle and we use the Pythagorean Theorem )

Hence, we have:

$10^2=L^2+W^2\\\\i.e.\\\\W^2=100-L^2\\\\W=\pm \sqrt{100-L^2}$

But we know that width can't be negative. It has to be greater than 0.

Hence, we have:

$W=\sqrt{100-L^2}$

Now, we know that the Perimeter of a rectangle is given by:

$Perimeter=2(L+W)$

Here we have:

$Perimeter=2(L+\sqrt{100-L^2})$

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