All categories

3 years ago

How can i find the x and y intercepts of a graph equation? (ex. y+ x-4)

Mathematics

1 answer:

brilliants [131]3 years ago

6 0

X and y = 4

I hope this helps!

You might be interested in

Is abc def name the postulates that applies

geniusboy [140]

Answer:

The answer is C. AAA is not a congruency postulate because the side lengths may be different sizes although the angles are the same.

4 0

3 years ago

PLEASE HELP!! i'm writing a test and i have no idea how to do this. (I'm giving 30 points)

Vesna [10]

Answer:

12/y

Step-by-step explanation:

if you see in the picture the first three numbers 3,6 and 9 you add 3 in each number like 3+3=6 then 6=3 = 9 and 9 + 3 = 12 and so on. ( 45 also comes in this pattern )

have a wonderful day

8 0

2 years ago

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago

30000x^2 + 2x + 1200

jasenka [17]

Answer: 2(15000x2)+x+600)

Step-by-step explanation:

8 0

3 years ago

Find the range. 3 –9 7 –1 5 –4 2

grin007 [14]

Put in order from smallest to largest
–9, –4, –1, 2, 3, 5, 7

Minimum = –9
Maximum = 7

Range = 7 - (-9) = 7 + 9 = 16

Range = the difference between the maximum and minimum data values

hope it helps

7 0

3 years ago