They are called transformations.
Y = 1 + i
<span>(1 + i)^3 - 3 * (1 + i)^2 + k - 1 = -i </span>
<span>(1 + 3i + 3i^2 + i^3) - 3 * (1 + 2i + i^2) + k - 1 = -i </span>
<span>1 + 3i - 3 - i - 3 - 6i + 3 + k - 1 = -i </span>
<span>1 - 3 - 3 + 3 - 1 + 3i - i - 6i + k = -i </span>
<span>-3 - 4i + k = -i </span>
<span>k = 4i - i + 3 </span>
<span>k = 3i + 3 </span>
<span>k = 3 * (1 + i) </span>
<span>k = 3y</span>
=18 sqrt2+15 sqrt2=33 sqrt 2
Answer:
~ 7 years
Step-by-step explanation:
2 = (1 + .1/4)^(4t)
2 = (1.025)^(4t)
Take the log of both sides
log2 = 4t * log1.025
divide both sides by log1.025
log2/log1.025 = 4t
28.07103452593863 = 4t
Divide both sides by 4
7.017758631484657 = t
~ 7 years
Answer:
if you go on calculator soup just input the numbers and what type of triangle it is and it will solve it for you
