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pychu [463]
3 years ago
9

In June, Meg runs a race 10 seconds faster than she did in April. Let y represent her finishing time for the race in April. Whic

h expression represents her faster time in June?
Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0
Answer: The expression that represents Meg's finishing time in June is "y - 10".

The problem started with Meg running in April. She had a time in April and we called it "y".

Now, Meg ran again in June. In June, she did 10 seconds faster. So it makes since that we need to subtract 10 from her April time, "y". Therefore, the expression is simply "y - 10".
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