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3 years ago

12

A superconducting solenoid has 3300 turns per meter and can carry a maximum current of 4.1 ka. find the magnetic field strength

in the solenoid.

2 answers:

jeyben [28]3 years ago

8 0

B = μ x n x I = 1.25 x 10^-6 x 3300 x 4.1 x 10^3
= 16.91 T

avanturin [10]3 years ago

7 0

Hope this helps you.

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Answer:

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Explanation:

By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation

$\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))$

Where

L = Thickness

n = Index of refraction of each material

$\lambda = Wavelength$

Our values are given as

$\Phi = 7(2\pi)L=tn_1 = 1.58n_2 = 1\lambda = 550nm$

Replacing our values at the previous equation we have

$\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))$

$t = \frac{7*550}{1.58-1}\\t = 6637.931nm \approx 6.64\mu m$

the thickness of the mica is 6.64μm

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