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topjm [15]
1 year ago
10

What observations of the martian surface led lowell to the conclusion that intelligent life forms existed on mars?

Physics
1 answer:
Alexus [3.1K]1 year ago
3 0

Icecaps that are dissolving, a system of canal-like geometric features, and various pitch black surface markings are all thought to be vegetation are the observations of the martian surface led Lowell to the conclusion that intelligent life forms existed on Mars.

<h3>What is a solar system?</h3>

It is a system that collection of all the planets and spatial bodies revolving around the sun because of the gravitational pull of the sun.

Our Solar System is based on a heliocentric model in which the Sun is assumed to reside at the central point of the planetary system.

In other words, the Sun is at the center while the Earth and other planetary bodies revolve around it.

Lowell came to the conclusion that intelligent life existed on Mars based on his observations of the martian surface, which included melting icecaps, a network of geometric patterns that resemble canals, and numerous markings on the completely black surface that are believed to be flora.

Learn more about Solar systems from here,

brainly.com/question/12075871

#SPJ4

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Which of the following is a correct<br> definition of the word "contingencies"?
Elden [556K]

Answer:

I already told ya

Explanation:

i got brainly so i could learn

3 0
2 years ago
Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 4.86 and angle θA = 23.5 ∘ measured in the sense from the +x
trasher [3.6K]

Answer:

(A⃗ ×B⃗ )⋅C⃗  = 69.868

Explanation:

We simplify the cross product first, thereafter the solution of the cross product is now simplified with the dot product as shown in the step by step calculation in the attachment

4 0
3 years ago
while racing on a flat track, a car rounds a curve of 28m radius and instantaneously experiences a centripetal acceleration of 1
liubo4ka [24]
When a body strictly moves on a curve, it's velocity at a point is tangential to the curve at that point.

Centripetal acceleration is the acceleration that a body experiences by the virtue of change in it's tangential velocity. It is directed towards the centre and mathematically is v^2/R where v is the speed at the instant.

So, 18 = v^2/R
v^2 = 504
v = 6√14
4 0
3 years ago
Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A
Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

\omega f^2=\omega o^2+2*\alpha*\theta

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

\tau=I*\alpha

\alpha=\tau/I     =>     \alpha = 0.5rad/s^2

Now we can calculate the final velocity:

\omega f = 8.68rad/s

Finally, we calculate the total work:

W= 1/2*I*\omega f^2 = 1883.56J

Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":

W = 1884J

3 0
3 years ago
A car enters a level, unbanked semi-circular hairpin turn of 100 m radius at a speed of 28 m/s. The coefficient of friction betw
meriva

Answer:

As  28m/s = 28m/s

Explanation:

r = the radius of the curve

m =  the mass of the car

μ = the coefficient of kinetic friction

N = normal reaction

When rounding the curve, the centripetal acceleration is

a = \frac{v^{2}}{r}

therefore

\mu mg = m \frac{v^{2}}{r} \\\\ \mu =  \frac{v^{2}}{rg}

v = \sqrt{\mu rg}

\mu = \sqrt{0.8 \times 100\times9.8} \\\\= 28m/s

As  28m/s = 28m/s

8 0
3 years ago
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