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2 years ago

What observations of the martian surface led lowell to the conclusion that intelligent life forms existed on mars?

1 answer:

3 0

Icecaps that are dissolving, a system of canal-like geometric features, and various pitch black surface markings are all thought to be vegetation are the observations of the martian surface led Lowell to the conclusion that intelligent life forms existed on Mars.

<h3>What is a solar system?</h3>

It is a system that collection of all the planets and spatial bodies revolving around the sun because of the gravitational pull of the sun.

Our Solar System is based on a heliocentric model in which the Sun is assumed to reside at the central point of the planetary system.

In other words, the Sun is at the center while the Earth and other planetary bodies revolve around it.

Lowell came to the conclusion that intelligent life existed on Mars based on his observations of the martian surface, which included melting icecaps, a network of geometric patterns that resemble canals, and numerous markings on the completely black surface that are believed to be flora.

Learn more about Solar systems from here,

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A ball is dropped from a height of 10m. At the same time, another ball is thrown

soldi70 [24.7K]

5.1 m

Explanation:

Let's set the ground as our reference point. Let's also call the dropped ball to be ball #1 and its height above the ground at any time t is given by

$y_1 = 10 - \frac{1}{2}gt^2$ (1)

where 10 represents its initial height or displacement of 10 m above the ground. At the same time, the displacement of the second ball with respect to the ground $y_2,$ is given by

$y_2 = v_0t - \frac{1}{2}gt^2$ (2)

At the instant the two balls collide, they will have the same displacement, therefore

$y_1 = y_2 \Rightarrow 10 - \frac{1}{2}gt^2 = v_0t - \frac{1}{2}gt^2$

$v_0t = 10\:\text{m}$

Solving for t, we get

$t = \dfrac{10\:\text{m}}{v_0} = \dfrac{10\:\text{m}}{10\:\text{m/s}} = 1\:\text{s}$

We can use either Eqn(1) or Eqn(2) to hind the height where they collide. Let's use Eqn(1):

$y_1 = 10\:\text{m} - \frac{1}{2}(9.8\:\text{m/s}^2)(1\:\text{s})^2$

$\:\:\:\:\:\:\:= 5.1\:\text{m}$

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aluminum has 13 electrons. how many electrons are found in the outermost energy level for this atom which energy level is the ou

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