1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LekaFEV [45]
3 years ago
14

Beat frequencies are caused by?

Physics
1 answer:
Margarita [4]3 years ago
3 0

Answer:Interference

Explanation:destructive interference

You might be interested in
I need help with this question, could you help me? :))) ASAP
Pepsi [2]
Oh ya the correct answer for this is B I think because structure B
4 0
2 years ago
A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal
Dmitry [639]
The resultant force on the animal = Resultant mass * total acceleration 
F = 0.2 * 2.5 to the right
F = 0.5 to the right.

As, girl exerting a force of 3.5 N & it's not mentioned that she is in right or left, so the force exerting by boy would be either:
3.5-0.5 = 3  OR  3.5+0.5 = 4

If boy exerting a greater force then, answer will be 4 N & if girl exerting a greater force the, answer will be 3 N

Hope this helps!
3 0
3 years ago
Read 2 more answers
Greg throws a 2.8-kg pumpkin horizontally off the top of the school roof in order to hit Mr. H's car. The car has parked a dista
Igoryamba

Answer:

The horizontal velocity is v = 9.2 m/s

Explanation:

From the question we are told that

     The mass of the pumpkin is  m = 2.8 \ kg

      The distance of the the car from the building's base is  d = 13.4 \ m

       The height of the roof is h = 10.4 \ m

       

The height is mathematically represented as

         h = \frac{1}{2} gt^2

Where g is the acceleration due to gravity which has a value of g =9.8 \ m/s^2

substituting values

          10.4= 0.5 * 9.8 * t

making the time taken the subject of the formula

         t = \frac{10.4}{0.5 * 9.8 }

          t = 1.457 \ s

The speed at which the pumpkin move horizontally can be represented mathematically  as

                         v = \frac{d}{t}

substituting values

                     v =\frac{13.4}{1.457}

                     v = 9.2 m/s

7 0
2 years ago
A coiled telephone cord forms a spiral with 90.0 turns, a diameter of 1.30 cm, and an unstretched length of 57.0 cm. Determine t
Vinvika [58]

Answer:

2.36 μ H

Explanation:

Given,

Number of turns= 90

diameter = 1.3 cm = 0.013 m

unscratched length = 57 cm  = 0.57 m

Area, A = π r²

            = π x 0.0065² = 1.32 x 10⁻⁴ m²

 we know,

   L = \dfrac{\mu_0N^2A}{l}

   L = \dfrac{4\pi \times 10^{-7}\times 90^2\times 1.32\times 10^{-4}}{0.57}

    L = 2.36 μ H

Hence, the inductance of the unstretched cord is equal to 2.36 μ H

8 0
3 years ago
Returning once again to our table top example of a horizontal mass on a low-friction surface with m = 0.254 kg and k = 10.0 N/m
Julli [10]

Explanation:

Given that,

Mass = 0.254 kg

Spring constant [tex[\omega_{0}= 10.0\ N/m[/tex]

Force = 0.5 N

y = 0.628

We need to calculate the A and d

Using formula of A and d

A=\dfrac{\dfrac{F_{0}}{m}}{\sqrt{(\omega_{0}^2-\omega^{2})^2+y^2\omega^2}}.....(I)

tan d=\dfrac{y\omega}{(\omega^2-\omega^2)}....(II)

Put the value of \omega=0.628\ rad/s in equation (I) and (II)

A=\dfrac{\dfrac{0.5}{0.254}}{\sqrt{(10.0^2-0.628)^2+0.628^2\times0.628^2}}

A=0.0198

From equation (II)

tan d=\dfrac{0.628\times0.628}{((10.0^2-0.628)^2)}

d=0.0023

Put the value of \omega=3.14\ rad/s in equation (I) and (II)

A=\dfrac{\dfrac{0.5}{0.254}}{\sqrt{(10.0^2-3.14)^2+0.628^2\times3.14^2}}

A=0.0203

From equation (II)

tan d=\dfrac{0.628\times3.14}{((10.0^2-3.14)^2)}

d=0.0120

Put the value of \omega=6.28\ rad/s in equation (I) and (II)

A=\dfrac{\dfrac{0.5}{0.254}}{\sqrt{(10.0^2-6.28)^2+0.628^2\times6.28^2}}

A=0.0209

From equation (II)

tan d=\dfrac{0.628\times6.28}{((10.0^2-6.28)^2)}

d=0.0257

Put the value of \omega=9.42\ rad/s in equation (I) and (II)

A=\dfrac{\dfrac{0.5}{0.254}}{\sqrt{(10.0^2-9.42)^2+0.628^2\times9.42^2}}

A=0.0217

From equation (II)

tan d=\dfrac{0.628\times9.42}{((10.0^2-9.42)^2)}

d=0.0413

Hence, This is the required solution.

5 0
3 years ago
Other questions:
  • A una distancia de 12.0 m dsde una fuente puntual, el nivel de intensidad es de 70dB. A que distancia desde la fuente el nivel d
    14·1 answer
  • A 2.0-kg mass (mA) and a 4.0-kg mass (mB) are connected to a lightweight cord that passes over a frictionless pulley. The pulley
    10·1 answer
  • How many miles is the moon from the earth
    11·1 answer
  • A bridge is supported by two piers located 14 meters apart. Both the left and right piers provide an upward force on the bridge,
    13·1 answer
  • El punto de fusión del plomo es de 327 °C y su punto de ebullición, de 1750 °C. a) ¿En qué estado se encontrará un trozo de plom
    10·1 answer
  • Two people carry a heavy electric motor by placing it on a light board 1.50 m long. One person lifts at one end with a force of
    14·1 answer
  • Which is a disadvantage of using wind as an energy source? Check all that apply.
    6·2 answers
  • Tech A says the leads on a multimeter are negative and positive. Tech B says the test leads on an oscilloscope that we normally
    13·1 answer
  • 2. Ms. Evelyn lined up her students at recess on the soccer field. She told each student to kick a soccer ball as hard as they c
    11·1 answer
  • 9.The force of gravity between two asteroids is 10,000 newtons (N).
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!