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Reptile [31]
2 years ago
12

Leeza did this to solve an equation. Did she makes an error 4x=7+3(2x-5) 4x=7+6x-5

Mathematics
2 answers:
katrin [286]2 years ago
8 0

Yes, there was a mistake in applying the distributive property. If you have to perform

3(2x-5)

you have to multiply both terms in the parenthesis by 3, not just the first one.

So, the correct expansion would be

3(2x-5) = 3\cdot 2x - 3 \cdot (-5) = 6x-15

sertanlavr [38]2 years ago
4 0

she has not distributed - 5 by 3 = - 15

4x = 7 + 3(2x - 5) ( distribute by 3 )

4x = 7 + 6x - 15 ( subtract 6x from both sides )

4x - 6x = 7 - 15

- 2x = - 8 ( divide both sides by - 2 )

x = \frac{- 8}{- 2} = 4


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X+2y=6 <br> SHOW ALL OF YOUR WORK!
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A pound of guinea pig pellets is about 3 cups of food.Each guinea pig eats 1/4 cup is pellets a day. How many days will the pell
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The pellet will last after 12 days

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* Lets change the story problem to equations to solve it

- There is a pound of guinea pig pellets

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- Each guinea pig eats 1/4 cup of pellets a day

* Lets use these information to solve the problem

∵ One pound of guinea = 3 cups of food

∵ The guinea pig eats 1/4 cup a day

- The pig can finish one cup in four days

∵ The number of days = number of cups ÷ the eaten in a day

∵ The number of cup = 3 cups

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4 0
3 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
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