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3 years ago

Balance the following chemical equations:

Chemistry

2 answers:

quester [9]3 years ago

5 0

The first one will be 2 1 -> 2 1
Second is 2 3 -> 6 1

sammy [17]3 years ago

5 0

1.)2 1 -> 2 1
2.) 2 3 -> 6 1

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BRAINLIEST AND 30 POINTS! concept map for four types of intermolecular forces and a certain type of bond is shown.

Sphinxa [80]

D represents ion-dipole forces that are stronger than the force C.

Explanation:

D represents the ion-dipole force.

C represents the H-bonding forces.

ion-dipole force is a force that is due to electrostatic attraction and has a dipole between an ion and a neutral molecule.

It is electrostatic in nature.

A hydrogen bond is the force between the hydrogen with the electro negative atom of one molecule, to electro negative atom of some other molecule. such as: O, F, N

Ion dipole force is stronger than the H-bonding.

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3 years ago

Ben works as a medical assistant. He needs to take a patient's vitals, but the patient is refusing to cooperate. He hasn't exper

mariarad [96]

Answer:

THE CORRECT ANSWER IS COMMAND.HOPE IT HELP YOU

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3 years ago

Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti

gayaneshka [121]

Answer : The value of $K$ for this reaction is, $2.6\times 10^{15}$

Explanation :

The given chemical reaction is:

$CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)$

Now we have to calculate value of $(\Delta G^o)$ .

$\Delta G^o=G_f_{product}-G_f_{reactant}$

$\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]$

where,

$\Delta G^o$ = Gibbs free energy of reaction = ?

n = number of moles

$\Delta G^0_{(HCH_3CO_2(g))}$ = -389.8 kJ/mol

$\Delta G^0_{(CH_3OH(g))}$ = -161.96 kJ/mol

$\Delta G^0_{(CO(g))}$ = -137.2 kJ/mol

Now put all the given values in this expression, we get:

$\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]$

$\Delta G^o=-89.4kJ/mol$

The relation between the equilibrium constant and standard Gibbs, free energy is:

$\Delta G^o=-RT\times \ln K$

where,

$\Delta G^o$ = standard Gibbs, free energy = -89.4 kJ/mol = -89400 J/mol

R = gas constant = 8.314 J/L.atm

T = temperature = $30.0^oC=273+30.0=303K$

$K$ = equilibrium constant = ?

Now put all the given values in this expression, we get:

$-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K$

$K=2.6\times 10^{15}$

Thus, the value of $K$ for this reaction is, $2.6\times 10^{15}$

4 0

3 years ago

Calculate the density of sulfuric acid from the information that 35.4 mL of the acid masses 65.14 g.

vladimir1956 [14]

Answer:

<h3>The answer is 1.84 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{65.14}{35.4} \\ = 1.840112994...$

We have the final answer as

Hope this helps you

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3 years ago

A Lewis acid is a substance that can

katrin2010 [14]

Accept a pair of nonbonding electrons,a Lewis acid is an electron-pair acceptor. A Lewis<span> base is any </span>substance, such as the OH-<span> ion, that </span>can<span> donate a pair of nonbonding electrons. </span>A Lewis<span> base is therefore an electron-pair donor.</span>

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3 years ago