The volume occupied by one mole of any gas at standard temperature(0o) and pressure(1 atm) is 22.4 litres. This volume is a close approximation and different gases vary slightly. The molar volume of any gas at S.T.P. is 22.4L .The mole of any gas can therefore be found using the expression on the right.
Answer:
v2= 5.404L
Explanation:
using Boyle's law
p1 x v1 = p2 x v2
101.325 x 4.31 = 80.8 x v2
v2= (101.325 x 4.31)\80.8
v2= 5.404L
Answer:
The temperature at 581.2 mL volume was 242.8 K.
Explanation:
Using Charle's law
Given ,
V₁ = 581.2 mL
V₂ = 830.5 mL
T₁ = ?
T₂ = 347 K
Using above equation as:
<u>The temperature at 581.2 mL volume was 242.8 K.</u>
The correct answer would be the last one.