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stellarik [79]
3 years ago
14

Eddie is performing an experiment. He asked the question what type of soil makes plants grow the fastest. He has four plants. He

gives Plant #1 with potting soil,Plant #2 with sand, Plant #3 with dirt from his yard, and Plant #4 with gravel. All of the plants are kept on the same shelf next to the window and receive the same amount of water. After 4 months, Plant #1 is 100 cm tall, Plant #2 & #3 are 115 cm tall, and Plant #4 is 12 cm tall.
What is the Manipulated Variable in this Experiment?

What is the Responding Variable?

Please help me!
Chemistry
1 answer:
Bezzdna [24]3 years ago
4 0
Manipulated variable: the types of soil
Responding variable: how much t the plants grow
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What is the molality, m, of an aqueous solution of ammonia that is 12.83 M NH3 (17.03 g/mol)? This solution has a density of 0.9
daser333 [38]

Answer:

Molality = 18.5 m

Explanation:

Let's analyse data. We want to determine molality which means mol of solute / 1kg of solvent. (Hence we need, the moles of solute and the mass of solvent in kg)

12.83 M means molarity → mol of solute in 1L of solution

Density refers always to solution → Mass of solution / Volume of solution

1L = 1000 mL

We can determine the mass of solution with density

0.9102 g/mL = Mass of solution / 1000 mL

Mass of solution = 0.9102 g/mL . 1000 mL → 910.2 g

Let's convert the moles of solute (NH₃) to mass

12.83 mol . 17.03 g/ 1 mol = 218.5 g

We can apply this knowledge:

Mass of solution = Mass of solvent + Mass of solute

910.2 g = Mass of solvent + 218.5 g

910.2 g - 218.5 g = 691.7 g → Mass of solvent.

Let's convert the mass in g to kg

691.7 g . 1kg / 1000 g = 0.6917kg

We can determine molalilty now → 12.83 mol / 0.6917kg

Molality = 18.5 m

6 0
3 years ago
1. calculate the the reaction of gas, F 2 (g) with H 2 O(l) water form and O 2 (e).
Sever21 [200]

hope this helped.:)

Explanation:

Yes, the number of moles of oxygen gas produced by your reaction under those conditions for pressure and temperature will be 0.0025.

Hydrogen peroxide,  

H

2

O

2

, decomposes to give water and oxygen gas according to the balanced chemical equation

2

H

2

O

2

(

a

q

)

→

2

H

2

O

(

l

)

+

O

2

(

g

)

You've collected 0.061 L of oxygen gas at 295.15 K and 1 atm, so you've got all the data you need to calculate the number of moles of oxygen gas produced by using the ideal gas law equation

P

V

=

n

R

T

⇒

n

=

P

V

R

T

n

O

2

=

1

atm

⋅

0.061

L

0.082

L

⋅

atm

mol

⋅

K

=

0.0025 moles

So, if this was your first question, then yes, your reaction produced 0.0025 moles of oxygen gas.

I find the second part of your question to be a little confusing. You were given the density of the hydrogen peroxide solution, so are you supposed to use that to determine the theoretical number of moles of oxygen for this reaction?

I'm not sure what  

100%

H

2

O

2

=

1.02 g/mL  

means, do you have a certain volume of hydrogen peroxide solution?

SIDE NOTE According to the additional information posted by Heather, it turns out that the initial hydrogen peroxide solution had a volume of 5 mL.

Even with the volume of the initial solution, you'd need its percent concentration to try and determine exactly how many moles you had present before the reaction.

Once you know how many moles of hydrogen peroxide you had, assume that all of the react and use the  

2

:

1

mole ratio that exists between  

H

2

O

2

and  

O

2

to get the number of moles of oxygen your reaction could have produced.

7 0
3 years ago
My science teacher trying to be cool
Helga [31]

Answer:

omg lol XD

Explanation:

3 0
2 years ago
How many electrons are in the n = 2 shell of a magnesium atom?
Montano1993 [528]

Answer:

eight

Explanation:

That means there are 12 electrons in a magnesium atom

hope this helps

8 0
2 years ago
Find the percentage composition of a compound that contains 1.94 g of carbon, 0.48 g of hydrogen, and 2.58 g of sulfur.
Svetradugi [14.3K]

Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

Explanation :

To calculate the percentage composition of element in sample, we use the equation:

\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100

Given:

Mass of carbon = 1.94 g

Mass of hydrogen = 0.48 g

Mass of sulfur = 2.58 g

First we have to calculate the mass of sample.

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur

Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g

Now we have to calculate the percentage composition of a compound.

\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%

\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%

\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%

Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

3 0
3 years ago
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