Answer:
3.0 L O₂
Explanation:
If CO reacts at STP, it means that there are 1.0 moles of CO. To find the moles of O₂, you need to use the mole-to-mole ratio from the given equation.
1.0 moles CO 1 mole O₂
---------------------- x --------------------- = 0.5 moles O₂
2 moles CO
To calculate the liters of oxygen, you need to use Avogadro's Law:
V₁ / N₁ = V₂ / N₂
In this equation, "V₁" and "N₁" represent the volume and moles of the first molecule. "V₂" and "N₂" represent the volume and moles of the second molecule. You can plug the given and calculated values into the equation and simplify to isolate V₂.
V₁ = 6.0 L V₂ = ? L
N₁ = 1.0 moles N₂ = 0.5 moles
V₁ / N₁ = V₂ / N₂ <----- Avogadro's Law
(6.0 L) / (1.0 moles) = V₂ / (0.5 moles) <----- Insert values
6.0 = V₂ / (0.5 moles) <----- Simplify left side
3.0 = V₂ <----- Multiply both sides by 0.5
**I am not 100% confident on this answer. Please let me know if it is incorrect**
Well, 2 litres is 2 kilograms. 1000 grams = 1 kilogram
So that means that 2 litres of water = 2000 grams
The number of mole of Ca reacted is:
4.86 g Ca/ (40.08 g/mol Ca)= 0.121 mol Ca
Because Ca reacted completely with oxygen and there is 2 mol Ca, there is 1 mol O2 reacted.
Total mass of oxygen that reacted is:
0.121 mol Ca* (1mol O2/ 2 mol Ca)* (32 g O2/ 1 mol O2)= 1.94 g O2 reacted.
Hope this would help~
Answer:
Astatine: Halogen
Nitrogen: Non-Metal
Krypton: Non-Metal, Noble Gas
Chlorine: Non-Metal
Sulfur: Non-metal
Explanation:
Following are the possible isomers of secondary alcohol and ketones for six carbon molecules. In order to distinguish between sec. alcohol and ketone we can simply treat the unknown compound with acidified Potassium Dichromate (VI) in the presence of acid. If with treatment with unknown compound the colour of K2Cr2O7 (potassium dichromate VI) changes from orange to green then it is confirmed that the unknown compound is sec. alcohol, or if no change in colour is detected then ketone is confirmed. This is because ketone can not be further oxidized while, sec. alcohol can be oxidized to ketones as shown below,
