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Simora [160]
3 years ago
15

What was the oxygen crisis

Chemistry
1 answer:
salantis [7]3 years ago
8 0
The Great Oxidation Event (GOE), sometimes also called the Great Oxygenation Event, Oxygen Catastrophe, Oxygen Crisis, Oxygen Holocaust,[2] or Oxygen Revolution, was a time period when the Earth's atmosphere and the shallow ocean first experienced a rise in oxygen, approximately 2.4 billion years ago (2.4 Ga) to 2.1–2.0 Ga during the Paleoproterozoic era.[3] Geological, isotopic, and chemical evidence suggests that biologically produced molecular oxygen (dioxygen, O2) started to accumulate in Earth's atmosphere and changed Earth's atmosphere from a weakly reducing atmosphere to an oxidizing atmosphere,[4] causing many existing species on Earth to die out.[5] The cyanobacteria producing the oxygen caused the event which enabled the subsequent development of multicellular forms.
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What is the charge on an atom with an equal number of protons and electrons?
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Answer: the answer is a netrual bond

Explanation: a netural bond happens when the number of electrons are the same as the number of protons.

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Massive stars have lower absolute brightness true or false
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A gas with a volume of 8 L at a temperature of 473K is switched to a new container with a temperature of 350K. If the pressure r
Digiron [165]

Answer:

The new  volume is 5.92 L,  which is approximately 6 L

Explanation:

As the gas temperature increases, the molecules move faster and take less time to reach the walls of the container. This means that the number of crashes per unit of time will be greater. That is, there will be an increase (for an instant) in the pressure inside the container and the volume will increase.

So Charles's Law is one of the gas laws that relates the volume and temperature of a certain amount of gas at constant pressure and says that:

  • If the temperature increases the volume increases
  • If the temperature decreases the volume decreases

Mathematically this is expressed by:

\frac{V}{T}=k

When you want to study two different states, an initial and a final one of a gas, this law is expressed by:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1: 8 L
  • T1: 473 K
  • V2: ?
  • T2: 350 K

Replacing:

\frac{8 L}{473K} =\frac{V2}{350K}

Solving:

V2=350K*\frac{8L}{473K}

V2=5.92 L

<u><em>The new  volume is 5.92 L,  which is approximately 6 L</em></u>

5 0
3 years ago
How many kilograms of oxygen did Samantha need to utilize to react with 36.29 kg of triglycerides (C55H104O6)?
Paraphin [41]

Answer:

105.33Kg of O2.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

C55H104O6 + 78O2 —> 55CO2 + 52H2O

Step 2:

Determination of the masses of C55H104O6 and O2 that reacted from the balanced equation.

This is illustrated below:

Molar mass of C55H104O6 = (12x55) + (104x1) + (16x6) = 860g/mol

Mass of C55H104O6 from the balanced equation = 1 x 860 = 860g.

Divide the mass of C55H104O6 by 1000 to express in kg i.e

Mass of C55H104O6 = 860/1000= 0.86Kg

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 78 x 32 = 2496g.

Divide the mass of O2 by 1000 to express in kg i.e

Mass of O2 = 2496/1000 = 2.496kg.

From the balanced equation above,

0.86kg of C55H104O6 reacted with 2.496Kg of O2.

Step 3:

Determination of the mass of O2 in kg needed to react with 36.29 kg of triglycerides (C55H104O6).

This can be obtained as follow:

From the balanced equation above,

0.86kg of C55H104O6 reacted with 2.496Kg of O2.

Therefore, 36.29 kg of C55H104O6 will react with = (36.29 x 2.496)/0.86 = 105.33Kg of O2.

Therefore, 105.33Kg of O2 is needed for the reaction.

5 0
3 years ago
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