Answer:
Given: 42 g of N2
Solve for O2 mass that contains the same number of molecules to 42 g of N2.
Solve for the number of moles in 42 g of N2
1 mole of N2 = (14 * 2) g = 28 g so the number of moles in 42 g of N2 is equal to 42 g / 28 g per mole = 1.5 moles
Solve for mass of 1 mole of oxygen
1 mole of O2 = 16 g * 2 = 32 g per mole
Solve for the mass of 1.5 moles of oxygen
mass of 1.5 moles of O2 = 32 g per mole * 1.5 moles
mass of 1.5 moles of O2 = 48 g
So 48 g of O2 contains the same number of molecules as 42 g of N2
1 mole of butane uses 4.5 moles of oxygen
0.1 mole of butane will use = 0.1 * 4.5 = 0.45 moles
P = 100 kPa = 100,000Pa
n = 0.45
T = 295 K
V = ?
Using PV = nRT
⇒ 100,000 * V = 0.45 * 8.314 * 295
⇒100,000 V = 1103.68
⇒ V = 1103.68/100,000 m³
⇒ V = 1103.68/100,000 * 1000 dm³
⇒ V = 11.036 dm³
You need 11.036 dm³ oxygen.
These are structural formulas of constitutional isomers of hexene, an alkene.
Both are acyclic, six-carbon chains, and they differ only in the position of the double bond. As constitutional isomers, both structures have the same molecular formula.
The first structure is of hex-1-ene (or 1-hexene).
The second structure is of (3E)-hex-3-ene [or (3E)-3-hexene].
Both structures have the molecular formula C₆H₁₂.
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Both synthesis and polymerization processes create chemically bonded combination of reactants. Synthesis is a reaction which uses various reactants to form one product, for example formation of water from hydrogen and oxygen. Polymerization illustrates the same process, wherein it uses simple monomer molecules in a reaction to create longer polymer chains, for example formation of proteins through polymerization of amino acids.
Answer:
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