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Nesterboy [21]
3 years ago
15

how many moles of silicon are in 245 g of silicon? a. 8.72 mol b. 28.0 mol c. 1.10 10-1 mol d. 6.90 103 mol

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
7 0
Atomic mass silicon = 28.085 u

1 mol Si ---------------- 28.085 g  
?  ------------------------ 245 g

245 x 1 / 28.085 =><span> 8.72 mol</span>

<span>answer A</span>
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Coal, which is primarily carbon, can be converted to natural gas, primarily ch4, by the exothermic reaction:
Leno4ka [110]
Unfortunately, your question is incomplete So, according to the attached picture of the complete question we will explain the answer:
according to the reaction equation:
C(s) + 2H2(g) ↔ CH4(g) ΔH° = -74.6KJ 
So the true answer will be D i and ii

- as by adding more C and it is a reactant so the reaction will go rightward to the product to decrease the C to achieve the equilibrium again, the movement of the reaction towards the products will make the CH4 increase

- and by decreasing the Heat and the heat here is as a product as the reaction is exothermic so by decreasing the heat the reaction will go toward the products to increase the heat and achieve the equilibrium again, and that also makes the CH4 increase as it is a product.
So the true answer is D i and ii as the attached photo 

5 0
4 years ago
Chromium-48 decays. After 6 half-lives, how much of the original nuclei would remain if we started with 600 g?
maw [93]

Answer:

1

Explanation:

2

3 0
3 years ago
what is the mass of carbon dioxide which contain the same number of molecules as are contained in 14 gram of oxygen?​
Ratling [72]

Answer:

Mass of CO2 WILL BE ~ 9.33 g

Explanation:

Moles of O2 = 14/18

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x/12 = 14/16

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3 0
3 years ago
The standard free-energy changes for the reactions below are given.Phosphocreatine → creatine + Pi ∆ G'° = –43.0 kJ/molATP → ADP
Anton [14]

Answer:

Gibbs free-energy of the reaction = (–12.5 kJ/mol)

Explanation:

The Gibbs free-energy of a reaction predicts the spontaneity or feasibility of a given chemical reaction.

<u>Given the standard Gibbs free energy changes</u>:

Phosphocreatine → creatine + Pi,  ∆G° = –43.0 kJ/mol     ...(1)

ATP → ADP + Pi , ∆G° = –30.5 kJ/mol      ....(2)

<u>Now to calculate the Gibbs free-energy of the given chemical reaction</u>: Phosphocreatine + ADP → creatine + ATP; the <em>equation (2) is reversed</em> to give:

ADP + Pi  → ATP, ∆G° = + 30.5 kJ/mol      ...(3)

<u>Now the equation (3) and (1) are added</u>, to give:

Phosphocreatine + ADP + Pi→ creatine + ATP + Pi

⇒ Phosphocreatine + ADP → creatine + ATP  

 

Therefore, to <u>calculate the Gibbs free-energy of the reaction, the standard Gibbs free energy changes of the equations (1) and (3) are added similarly</u>:

Gibbs free-energy of the reaction: ∆G° = (–43.0 kJ/mol) + ( + 30.5 kJ/mol) = (–12.5 kJ/mol)

<u><em>Therefore, the Gibbs free-energy of the reaction </em></u><u><em>= </em></u><u><em>(–12.5 kJ/mol)</em></u>

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