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Veseljchak [2.6K]
3 years ago
13

The formula for potential energy is mass x gravity x height. How much potential energy is in a 10 kg rock sitting on a cliff tha

t is 5 meters high?
Physics
1 answer:
Dovator [93]3 years ago
8 0

Answer:

490.5 J

Explanation:

m = Mass of rock = 10 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height from the ground = 5 m

The potential energy gives the energy that the body posseses due to its mass and height of the fall.

Potential energy is given by

U=mgh

\Rightarrow U=10\times 9.81\times 5

\Rightarrow U=490.5\ J

The potential energy of the rock which is at the given height is 490.5 J

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An instrument is thrown upward with a speed of 15 m/s on the surface of planet X where the acceleration due to gravity is 2.5 m/
Katen [24]
<h2>Answer: 12 s</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told <u>the instrument is thrown upward</u> from the surface, we will only use the equations related to the Y axis.

In this sense, the main movement equation in the Y axis is:

y-y_{o}=V_{o}.t-\frac{1}{2}g.t^{2}    (1)

Where:

y  is the instrument's final position  

y_{o}=0  is the instrument's initial position

V_{o}=15m/s is the instrument's initial velocity

t is the time the parabolic movement lasts

g=2.5\frac{m}{s^{2}}  is the acceleration due to gravity at the surface of planet X.

As we know y_{o}=0  and y=0 when the object hits the ground, equation (1) is rewritten as:

0=V_{o}.t-\frac{1}{2}g.t^{2}    (2)

Finding t:

0=t(V_{o}-\frac{1}{2}g.t^{2})   (3)

t=\frac{2V_{o}}{g}   (4)

t=\frac{2(15m/s)}{2.5\frac{m}{s^{2}}}   (5)

Finally:

t=12s

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